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schepotkina [342]
1 year ago
11

Triangle ADB, point C lies on segment AB and forms segment CD, angle ACD measures 90 degrees. Point A is labeled jungle gym and

point B is labeled monkey bars.
Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. If Beth places the swings at point D, how could she prove that point D is equidistant from the jungle gym and monkey bars?

If segment AC ≅ segment BC, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
If segment AD ≅ segment CD, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If segment AC ≅ segment BC, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If segment AD ≅ segment CD, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
Mathematics
1 answer:
Scrat [10]1 year ago
3 0

An <u>equidistant</u> point is a given point that is at the <em>same</em> <em>distance</em> from two <u>reference</u> points. Thus the appropriate <u>answer</u> is: If segment AC ≅ segment BC, then point D is equidistant from points A and B because a point on a <em>perpendicular bisector</em> is equidistant from the <u>endpoints</u> of the <u>segment</u> it intersects.

An <u>equidistant</u> point is a given point that is at the <em>same distance</em> from <u>two</u> <em>reference</em> points. Thus the <u>point</u> is said to be between the two points and at an <u>equal </u>distance.

A <em>bisector</em> is a line that <u>divides</u> a given line segment or angle into two <em>equal</em> parts or measures.

In the given question, it can be observed that the <u>swings</u> are o be placed in such a way that they would be at <em>the same distance</em> from the<u> jungle gym</u> and <u>monkey bars</u>.

Therefore, the <em>required answer</em> to the question is: If segment AC ≅ segment BC, then point D is <u>equidistant</u> from points A and B because a point on a <em>perpendicular bisector</em> is <u>equidistant</u> from the <em>endpoints</em> of the <u>segment</u> it intersects.

For more clarifications on equidistant point to given reference points, visit: brainly.com/question/929137

#SPJ1

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