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schepotkina [342]
2 years ago
11

Triangle ADB, point C lies on segment AB and forms segment CD, angle ACD measures 90 degrees. Point A is labeled jungle gym and

point B is labeled monkey bars.
Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. If Beth places the swings at point D, how could she prove that point D is equidistant from the jungle gym and monkey bars?

If segment AC ≅ segment BC, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
If segment AD ≅ segment CD, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If segment AC ≅ segment BC, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If segment AD ≅ segment CD, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
Mathematics
1 answer:
Scrat [10]2 years ago
3 0

An <u>equidistant</u> point is a given point that is at the <em>same</em> <em>distance</em> from two <u>reference</u> points. Thus the appropriate <u>answer</u> is: If segment AC ≅ segment BC, then point D is equidistant from points A and B because a point on a <em>perpendicular bisector</em> is equidistant from the <u>endpoints</u> of the <u>segment</u> it intersects.

An <u>equidistant</u> point is a given point that is at the <em>same distance</em> from <u>two</u> <em>reference</em> points. Thus the <u>point</u> is said to be between the two points and at an <u>equal </u>distance.

A <em>bisector</em> is a line that <u>divides</u> a given line segment or angle into two <em>equal</em> parts or measures.

In the given question, it can be observed that the <u>swings</u> are o be placed in such a way that they would be at <em>the same distance</em> from the<u> jungle gym</u> and <u>monkey bars</u>.

Therefore, the <em>required answer</em> to the question is: If segment AC ≅ segment BC, then point D is <u>equidistant</u> from points A and B because a point on a <em>perpendicular bisector</em> is <u>equidistant</u> from the <em>endpoints</em> of the <u>segment</u> it intersects.

For more clarifications on equidistant point to given reference points, visit: brainly.com/question/929137

#SPJ1

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indicate whether the measures 8, 14, and 16 can be the side lengths of a triangle. if they can, classify the triangle.
Aleksandr-060686 [28]

Answers:  

A triangle is possible.

The triangle is <u>acute</u> and <u>scalene</u>

=============================================================

Explanation:

We use the triangle inequality theorem to see if a triangle is possible with these side lengths.

Consider the side lengths a, b, and c. A triangle is possible if and only if the following 3 conditions hold true

  • a+b > c
  • a+c > b
  • b+c > a

Basically pick any two sides. If the sum is larger than the third side, then a triangle is possible.

-----------------

In this case we have: a = 8, b = 14, c = 16. The order of the a,b,c values doesn't really matter.

Then:

  • a+b = 8+14 = 22 which is larger than c = 16. So a+b > c is true.
  • a+c = 8+16 = 24 is larger than b = 14. So a+c > b is true.
  • b+c = 14+16 = 30 is larger than a = 8. So b+c > a is true.

All three inequalities mentioned are true; therefore, <u>a triangle is possible</u> with these side lengths.

-----------------

We'll use those a,b,c values in the converse of the pythagorean theorem to determine what kind of triangle this is. So far we know it's <u>scalene</u> because all three side lengths are different. It would be isosceles if it had exactly two equal sides, and equilateral if all 3 sides were the same length.

a^2+b^2 = c^2\\\\8^2+14^2 = 16^2\\\\260 = 256\\\\

The last equation is false, which tells us this triangle is not a right triangle. It's either acute or obtuse.

Since a^2+b^2 > c^2 is the case here, we can conclude the triangle is <u>acute</u>

If a^2+b^2 < c^2 was the case, then the triangle would be obtuse.

-----------------

Summary:

  • A <u>triangle is possible</u> with side lengths a = 8, b = 14, c = 16.
  • This triangle is <u>scalene</u> and <u>acute</u>
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