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3 years ago

Explain how you know if an equation has one solution, infinitely many solutions, or no solution

1 answer:

8 0

No solution would mean that there is no answer to the equation. It is impossible for the equation to be true no matter what value we assign to the variable. Infinite solutions would mean that any value for the variable would make the equation true. :)

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Mr.Lopez owns a home that sits on 7/8 of an acre. He has decided to plow up 1/4 of the property to create a garden. What fractio

vodomira [7]

In math, "of" almost always means "times".

"The property" is 7/8 acre.

So "1/4 of the property" means "1/4 times 7/8 acre".

1/4 x 7/8 = (1 x 7) / (4 x 8)

That's 7/32 .

Mr. Lopez hasn't plowed up anything yet, but his plan is to plow up 7/32 acre for his garden.

3 0

3 years ago

Express the complex number 6 in complex trigonometric form. [See Attachment for answer choices]

kvasek [131]

Its B
Bscous etheres bot away that the nymber sis would go that long

5 0

3 years ago

Billy has 1 gallon of paint. He is going to pour it into a paint tray that measures 10 inches wide, 14 inches long, and 4 cm dee

V125BC [204]

Answer:

The paint will not fill the tray by 10.53 cubic inches.

Step-by-step explanation:

We will find the volume of the paint tray and compare it with the volume of the gallon.

Given dimensions are:

Length = 14 inches

Width = 10 inches

Depth = 4 cm or $\frac{4}{2.54}=1.575$ inches

The volume is given by = length x width x depth

Volume = $14\times10\times1.575=220.50$ cubic inches

Volume of 1 gallon is given as = 231 cubic inches

We can see that volume of 1 gallon is more than volume of tray.

Difference = $231-220.50=10.5$ cubic inches.

So, the paint will not fill the tray by 10.53 cubic inches.

3 0

3 years ago

PLEASE HELP ME 100 POINTS

Ghella [55]

Answer:

Step-by-step explanation:

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5 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago