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krek1111 [17]
3 years ago
15

The school cafeteria serves tacos every 60 and cheeseburgers every eighth day.If tacos and cheeseburgers are both on today's men

u, and how many days will the next serve tacos and cheeseburgers on the same day?
Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0

Answer:

120 days

Step-by-step explanation:

Tacos are served every 60 days.

Cheeseburgers are served every 8 days.

Since, both Cheeseburgers and Tacos are served today, the next day on which both will be served is gotten by finding the Lowest Common Multiple of 60 and 8.

To find the LCM,

First, we express the numbers as a product of their prime factors.

60= 2X2X3X5=2²X3X5

8=2X2X2=2³

Next, we take each of the term with the highest power and multiply.

L.C.M = 2³X3X5=120

After 120 days, Cheeseburgers and Tacos will be served on the same day.

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Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,
Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is \dfrac{1}{6} = 0.1667 .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is   \dfrac{1}{6} .

      Numbers on the dice (X)                       P(X)

                      +1                                                 \frac{1}{6}

                      +2                                                \frac{1}{6}

                      +3                                                \frac{1}{6}

                      -4                                                 \frac{1}{6}

                      +5                                                \frac{1}{6}

                      -6                                                 \frac{1}{6}

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X)  =  \sum X \times P(X)

   =  (+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}

   =  \frac{1}{6} + \frac{2}{6} + \frac{3}{6} - \frac{4}{6} + \frac{5}{6} - \frac{6}{6}

   =  \frac{1+2+3-4+5-6}{6}

   =  \frac{11-10}{6}= \frac{1}{6}

Hence, the expected value of the points earned on a single roll in this game is  \frac{1}{6} = 0.1667 .

4 0
3 years ago
If h=2f/m+1 , solve the equation for F. Plz SHOW WORK!!!!
MArishka [77]
H=2f/m+1
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h-1=2f/m
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m*h-1=2f
divide 2 both sides
mh-1/2=F
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zavuch27 [327]

Answer:

IDK

Step-by-step explanation:

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Bas_tet [7]

Answer:

The numbers are 12, 21.

Step-by-step explanation:

x+(x+9)=33

x+x+9=33

2x+9=33

2x=33-9

2x=24

x=24/2

x=12

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x+9=12+9=21

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