Answer: John has an object suspended in the air. It has a mass of 50 kilograms and is 50 meters above the ground. Calculate the object's potential energy.
Step-by-step explanation:
Calculate the potential energy for a 2 kg basketball dropping from a height of 3.5 meters with a velocity of 9.8 m/sec².
Answer:
C. 185 ft
Step-by-step explanation:
The work is in the attached picture file, if you need it. Basically the question sets up a right triangle, for which the base is 200 and the height is the goal that you are solving for. It is given that the angle between hypotenuse and base is 42 degrees. For this you use tangent to say that
tan(42) = h / 200
200 tan (42) = h
h = 180 feet.
But then you must remember that this triangle starts 5 feet off of the ground. So you add the 5 feet and get 185 feet as the height of the tower.
Answer:
Step-by-step explanation:
Sales tax 25000(0.07) = $1,750.00
Property tax (25000 / 1000)(14.62) <u>= + $ 365.50</u>
Total tax $ 2115.50
Answer:
Average rate of fall = 
Step-by-step explanation:
Since they give you an expression for the position of the object as a function of time, one can derive the average velocity of the object during the first 3 seconds of the fall by estimating the position of the object at time 0, the position of the object at time 3 seconds, finding the displacement of the object (distance covered) in that interval of time (via a subtraction of these two quantities), and finally dividing this change by the elapsed time (3 seconds) thus using the concept that velocity is the quotient between distance covered over the elapsed time:
Average rate of fall = (h(3) - h(0))/ 3
Average rate of fall =
Answer:
2/12 + 3/12 + 3/12 + 2/12 + 5/12
Step-by-step explanation:
I hope I'm right
