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dem82 [27]
4 years ago
8

Jason plotted points on a number line at the four values below.

Mathematics
1 answer:
olga nikolaevna [1]4 years ago
3 0

Answer:

Point 5/3 is the farthest from 0

Step-by-step explanation:

Given

Points: 0.27, -1/4, 1.1, 5/3

Required

The farthest from zero

The first step is to convert all points to decimal;

Points: 0.27, -1/4, 1.1, 5/3

This becomes

Points: 0.27, -0.25, 1.1, 1.67

The next step is to calculate the absolute difference of each point from 0;

The farthest from 0 is the point with highest absolute difference

For 0.27

Absolute Difference = |0.27 - 0| = |0.27| = 0.27

For -0.25

Absolute Difference = |-0.25 - 0| = |-0.25| = 0.25

For 1.1

Absolute Difference = |1.1 - 0| = |1.1| = 1.1

For 1.67

Absolute Difference = |-1.67 - 0| = |-1.67| = 1.67

From the above calculations; point 1.67 or 5/3 is the farthest from 0

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4 years ago
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Olenka [21]

Answer:

∠A = 70°, ∠B = 50°, and ∠C = 60°.

Step-by-step explanation:

In a triangle ΔABC, ∠A + ∠B + ∠C = 180° ......... (1), we know from the property of triangle.

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If the exterior angle adjacent to ∠C is 120°, then ∠C = 180° - 120° = 60°.

Now, from equation (1), ∠A + ∠B = 180° - ∠C = 180° - 60° = 120° ......... (2)

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3 years ago
What is the distance in units between the points (8,-1) and (-2,-1) on a coordinate plane?
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Your given points are (8, -1) and (-2, -1).
The distance will be
\sqrt{(-1+1)^2+(-2-8)^2}  \\ =  \sqrt{100}  \\ =10.

But you could have recognized that both points have the same y-coordinate of -1, which means change in distance is determined by change in x-coordinates only.
Change in x-coordinates is |-8 - 2| = 10. There is absolute value because distance cannot be negative.
3 0
3 years ago
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