Answer:
-310, -1.5, 2, 25, 210
Step-by-step explanation:
Hope that helps
Answer:
L=4W
79/4=19.75
Step-by-step explanation:
Answer:
The speed of the plane in still air and the speed of the jet stream are 525 miles per hour and 75 miles per hour.
Step-by-step explanation:
From Mechanical Physics, we know that absolute velocity of the airplane () is equal to sum of the absolute velocity of the jet steam and the relative velocity of the airplane with respect to jet stream (velocity of the airplane in still air) (). Al velocities are measured in miles per hour. Let suppose that both jet stream and airplanes travels at constant velocity. Now, we construct the following system of linear equations:
Flight with the jet stream
(1)
Flight against the jet stream
(2)
The solution of this system of linear equations is:
,
The speed of the plane in still air and the speed of the jet stream are 525 miles per hour and 75 miles per hour.
Q5 C = 5(350-32)/9
≈ 176.6
≈ 177
Q6 A= 4/2 ( 3+5 )
= 16cm
The midpoint is given as (1,7)
We are given one endpoint (-8,3) which can represent (x1,y1).
We need to get the other endpoint represented by (x2,y2)
1- The x-coordinate:
The x-coordinate of the midpoint is calculated using the following rule:
Xmidpoint = (x1+x2) / 2
1 = (-8+x2) / 2
2 = -8 + x2
x2 = 2+8
x2 = 10
The x-coordinate of Q is 10
2- The y-coordinate:
The y-coordinate of the midpoint is calculated using the following rule:
Ymidpoint = (y1+y2) / 2
7 = (3+y2) / 2
14 = 3+y2
y2 = 14-3
y2 = 11
The y-coordinate of Q is 11
Based on the above calculations, the coordinates of point Q are (10,11)