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Fittoniya [83]
3 years ago
8

HELP ASAP PLEASE ONLY #4,6,8,10,12,14,16​

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

Step-by-step explanation:

Oof, all 6?  That's not fun.  

I'm going to show you one for the first bunch, (4-12) and hopefully you can get the rest.  If not let me know and I can more carefully work you through some others on here.

4)  So first we need the angle.  How do we find that?  Well, we know it's somewhere between 270 and 360 degrees (or 3pi/2 and 2pi radians) since it's in the fourth quadrant.    The method to finding the angle is ifferent for each quadrant, but it's nice to know around where you'll get.  Anyway,, if we take 360 and subtract that little space  that is unlabeled  we will know  the rest.    Hopefully that makes sense, but let me know if not, it's important to understand.  Maybe think of what happens if you add the two together, you get around the whole circle then.  

Anyway, to find that little sliver, we are going to construct a right triangle wherethe x axis is one side.  If you draw a line connecting point p and the x axis you have this right triangle.  I am going to call this sliver we don't know s.  ANyway, now we use trig here.  

s = arcsin(3/5) (you can find 5 pretty easily but let me know if you don't see it.)

You may think to use -3 instead of 3, and  it wouldn't be a huge mistake, it will just give you the negative version of what we want.  

Anyway, now we know theta is 360-s (or 2pi-s).  You can solve s or leave it as arcsin(3/5) so you don't have to round.

Now we can solve the trig functions.  If you don't know the sum and difference trig identities  you will have to round.  They are pretty simple formula though.  For instance, sin(2pi - arcsin(3/5)) = sin(2pi)cos(arcsin(3/5))-cos(2pi)sin(arcsin(3/5)) = 0 - 3/5 = -3/5  You will also want to know that s = arcsin(3/5) = arccos(4/5) = arctan(3/4).  ROunding will get you close but not exact.

Again, let me know ifyou need any more help, they should just be a lot of doing the same thing over and over and over again though.  

14)  For 14 and 16 you just need to know how the graphs of sin, cos and tan look.  Is this something you have trouble with?  Like could you draw the graphs at the intervals of increasing/ decrasing and all.  if not I can give a quick explanation.

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Reptile [31]

Answer: 2p because yes :)

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3 years ago
Help please, I need it
OlgaM077 [116]

Answer:

  2)  c)  (x-3)² + (y+2)² = 25

  5)  x^2 +y^2 -8x -16y +54 = 0

  6)  x^2 +y^2 -10x -12y +36 = 0

Step-by-step explanation:

2) The standard form equation for a circle is ...

  (x -h)^2 +(y -k)^2 = r^2

You are given the center: (h, k) = (3, -2) and a point on the circle. So, the equation will be ...

  (x -3)^2 +(y +2)^2 = r^2

Since we know a point on the circle we know that ...

  (7 -3)^2 +(1 +2)^2 = r^2 = 16 +9 = 25

So, the circle's equation is ...

  (x -3)^2 +(y +2)^2 = 25 . . . . . matches choice C

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5) As in the previous problem, the standard form equation is ...

  (x -4)^2 +(y -8)^2 = (-1-4)^2 +(7-8)^2 = 25+1 = 26

To put this in general form, we need to subtract 26 and eliminate parentheses.

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  x^2 +y^2 -8x -16y +54 = 0

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6) A circle tangent to the y-axis will have a radius equal to the x-value of the center point.

  (x -5)^2 +(y -6)^2 = 5^2

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8 0
4 years ago
The manager of a large apartment complex knows from experience that 120 units will be occupied if the rent is 450 dollars per mo
Sphinxa [80]

Answer:

To maximize revenue, the manager should charge $525

Step-by-step explanation:

Given.

Rent = $450.

Unit = 120

Yes assume our function to be F(x).

To maximise F(x), the function will be based how much of the available units (x) is less than the initial 120 units with a corresponding increase in revenue dollars of 5x above the initial revenue.

Initial Revenue = 450 * 120 = $54,000

F(x) = (120 - x)(450 + 5x)

Converting this into standard quadratic form;

F(x) = 54000 + 600x - 450x - 5x²

F(x) = 54000 + 150x - 5x²

F(x) = -5x² + 150x + 54000

Using axis of symmetry formula

(x = -b/2a) for a parabola to determine the x coordinate of the function's vertex (maximum point):

F(x) = -5x² + 150x + 54,000

Where a = -5

b = 150

x = -b/2a

x = -150/2(-5)

x = -150/-10

x = 15 units less than 120

Next is to calculate the corresponding value of F(x) .

By Substitution

F(x) = -5(15)² + 150(15) + 54000

F(x) = -1125 + 2250 + 54000

F(x) = 55,125 --- Maximum Revenue

Calculating the optimum monthly rent based upon the maximum revenue dollars divided by by the previously determined number of units (15) less than the initial 120 units:

Monthly Rent = 55,125/(120 - 15)

Monthly Rent = 55,125/105

Monthly Rent = $525

To maximize revenue, the manager should charge $525

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3 years ago
Graph the function f(x)=4x^2+ 3x - 1
Marizza181 [45]

Step-by-step explanation:

The graph of a quadratic function is a U-shaped curve called a parabola. One important feature of the graph is that it has an extreme point, called the vertex. If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function. If the parabola opens down, the vertex represents the highest point on the graph, or the maximum value. In either case, the vertex is a turning point on the graph. The graph is also symmetric with a vertical line drawn through the vertex, called the axis of symmetry.

Graph of a parabola showing where the x and y intercepts, vertex, and axis of symmetry are.

The

y

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y

-axis. The

x

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x

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4 0
3 years ago
Calc help pretty please
Gre4nikov [31]

Answer:

A.  77.4

Step-by-step explanation:

<u>Linear approximation formula</u>

L(x)=f(a)+f'(a)(x-a)

Given function:

f(x)=(x+1)^2

\boxed{\begin{minipage}{5.4 cm}\underline{Chain Rule for Differentiation}\\\\If  $y=f(u)$  and  $u=g(x)$  then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{\text{d}y}{\text{d}u}\times \dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}

\boxed{\begin{minipage}{5 cm}\underline{Differentiating $x^n$}\\\\If  $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=xn^{n-1}$\\\end{minipage}}

\boxed{\begin{minipage}{4 cm}\underline{Differentiating $ax$}\\\\If  $y=ax$, then $\dfrac{\text{d}y}{\text{d}x}=a$\\\end{minipage}}

Use the chain rule to differentiate the function.

\textsf{Let }\:y=u^2\:\textsf{ where }u=(x+1)

Differentiate the two parts separately:

  y=u^2 \implies \dfrac{\text{d}y}{\text{d}u}=2u

  u=x+1 \implies \dfrac{\text{d}u}{\text{d}x}=1

Put everything back into the chain rule formula:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =2u \times 1\\ & = 2u \\ & = 2(x+1)\\ & = 2x+2 \end{aligned}

\textsf{Therefore, }\:f'(x)=2x+2..

The <u>linear approximation</u> at a = 8 is:

\begin{aligned}L(x) & =f(a)+f'(a)(x-a)\\\\\implies L(x) & = f(8)+f'(8)(x-8)\\& = (8+1)^2+(2(8)+2)(x-8)\\& = 81+18(x-8)\\& = 18x-63\end{aligned}

Finally, substitute x = 7.8 into the <u>linear approximation equation</u>:

\begin{aligned}\implies L(7.8) & =18(7.8)-63\\& = 140.4-63\\& = 77.4\end{aligned}

4 0
2 years ago
Read 2 more answers
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