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juin [17]
3 years ago
15

Mountain Ski Corp. was set up to take large risks and is willing to take the greatest risk possible. Lakeway Train Co. is more t

ypical of the average corporation and is risk-averse.
Projects Returns:
Expected Value Standard
Deviation
A $ 527,000 $ 834,000
B 682,000 306,000
C 74,000 135,000
D 140,000 89,000

a-1. Compute the coefficients of variation. (Round your answers to 3 decimal places.)

Coefficient of
Variation
Project A
Project B
Project C
Project D

a-2. Which of the following four projects should Mountain Ski Corp. choose?


Project A
Project B
Project C
Project D

b.

Which one of the four projects should Lakeway Train Co. choose based on the same criteria of using the coefficient of variation?

Project A
Project B
Project C
Project D
Mathematics
1 answer:
nasty-shy [4]3 years ago
7 0
A-2: Project D.

b: Project A.

Not sure about a-1, hope I helped.
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Katie has read 32% of a book. If she has read 80 pages, how many more pages does Katie have left to read? Please explain
yawa3891 [41]
Keep note of these things before we start:
-Of is a keyword that tells us multiplication is being done
-x = total number of pages
-32% = 32/100 = .32

Okay, here we go:
32% of total number of pages = 80
.32 of x = 80
.32*x = 80
.32x = 80
.32x/.32 = 80/.32
x = 250

There are 250 pages in total in Katie's book.
To find out how many pages she has to read (y), subtract the pages read from the total:
TOTAL - PAGES READ = PAGES LEFT TO READ
250 - 80 = y
170 = y

Katie has 170 pages left to read
Hope this helps!
8 0
3 years ago
A=pt+q<br> p= -1, t=4 and q=6<br> work out the value of a
77julia77 [94]

Answer:

a = 2

Step-by-step explanation:

a = pt + q

p = -1

t = 4

q = 6

a = -1(4)+6

a = -4+6

a = 2

8 0
3 years ago
Martin earned the following scores on his last five tests.
Arada [10]
IQR= 18 is the interquartile range of his scores.
8 0
3 years ago
Find the exact area of the shaded please helppp ILL GIVE BRAINLIESTTTTTT
musickatia [10]

Answer:

The exact area is 5\pi

Step-by-step explanation:

The area of the major circle is subtracted from the area of the minor circle (blank)

Major circle

r=\frac{6}{2} =3

A=\pi r^{2} =\pi (3)^{2} =\pi (9)=9\pi

Minor circle:

r=\frac{4}{2} =2

A=\pi r^{2} =\pi (2)^{2} =\pi (4)=4\pi

The shaded area:

9\pi -4\pi =5\pi

Hope this helps

8 0
2 years ago
Please help me, i'm trying to graduate!!!
Svet_ta [14]
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.

The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151

Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.

Hope this makes sense.
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3 0
3 years ago
Read 2 more answers
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