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juin [17]
3 years ago
5

Select two lines that have a slope of -2

Mathematics
1 answer:
pishuonlain [190]3 years ago
8 0

Answer:

There are no two lines?

so we can't solve this!

sorry!!

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Heelp<br> plsss <br> just read it
goldfiish [28.3K]

Answer:

b

7 1/3 IT WONT LET ME PUT IT IN UGH

6 0
3 years ago
A website streams movies and television shows to millions of users. Employees know that the average time a user spends per sessi
oksian1 [2.3K]

Using the Central Limit Theorem, it is found that since the sample size is greater than 30, a normal approximation can be used, hence the test can be made.

<h3>Central Limit Theorem</h3>

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the sampling distribution is also approximately normal, as long as n is at least 30.

In this problem, the distribution of lengths is skewed, however, since the sample size is of 100 greater than 30, a normal approximation can be used, hence the test can be made.

To learn more about the Central Limit Theorem, you can check brainly.com/question/24663213

4 0
2 years ago
Help me please!!! i cant do these
LuckyWell [14K]

Answer:

sec(B)=b. ab/bc

sin(B)=c. ac/ab

csc(B)=f. ab/ac

cot(B)=a. bc/ac

tan(B)=e. ac/bc

cos(B)=d. bc/ab

Step-by-step explanation:

<u><em>SOHCAHTOA</em></u>

<u><em>Sine=Opposite/Hypotenuse</em></u>

<u><em>Cosine=Adjacent/Hypotenuse</em></u>

<u><em>Tangent=Opposite/Adjacent</em></u>

<u><em>SHACHOCotAO</em></u>

<u><em>Secant=Hypotenuse/Adjacent</em></u>

<u><em>Cosecant=Hypotenuse/Opposite</em></u>

<u><em>Cotangent=Adjacent/Opposite</em></u>

<u><em /></u>

6 0
2 years ago
A catering company loses $110 as a result of a delay.
faust18 [17]

Answer: Positive

Step-by-step explanation: It would be positive because the question is asking how much money they lost. The lost a positive amount of money.

7 0
1 year ago
Which equation could be used to find m∠E in △EFG? m∠E = cos–1(StartFraction 3 Over 4.6 EndFraction) m∠E = cos–1(StartFraction 4.
polet [3.4K]

Answer:

m\angle E=tan^{-1}(\frac{3}{4.6})

Step-by-step explanation:

The picture of the question in the attached figure

we know that

In the right triangle EFG

tan(E)=\frac{GF}{EF} ----> by TOA (opposite side divided by the adjacent side)

substitute

tan(E)=\frac{3}{4.6}

m\angle E=tan^{-1}(\frac{3}{4.6})

3 0
3 years ago
Read 2 more answers
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