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2 years ago

Consider 7×10^3. Write a pattern to find the value of the expression

Mathematics

2 answers:

kkurt [141]2 years ago

5 0

Answer:

7*10*10*10 = 7000

7*10 = 70

70*10 = 700

700*10 = 7000

Step-by-step explanation:

The given expression is:

7*10^3

Here 10^3 means that 10 will be multiplied 3 times:

7*10*10*10 = 7000

How did we get 7000?

7*10*10*10 = 7000

7*10 = 70

70*10 = 700

700*10 = 7000

We can also say that there are 7 1000s in 7000....

Strike441 [17]2 years ago

5 0

Answer: Hi! the notation 7×10^3 means 7*10*10*10, where 3 is the exponent.

You can think this notation as how many zeros you can add to the left (or right if the exponent is negative) of a number.

so 7×10^3 has an exponent equal to 3, so you add 3 zeros and get : 7000.

if we do the multiplication, 7*10*10*10 = (7*10)*10*10 = 70*10*10 = (70*10)*10 = 700*10 = 7000.

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Help help help help math

balu736 [363]

Answer:

A = 192

Step-by-step explanation:

r = 16/2 = 8

A = 3x(8)^2

8^2 = 64

A = 3 x 64 = 192

4 0

2 years ago

Read 2 more answers

A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03% chlorine. Starting at tequals0, city water conta

Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.

Remember, 1 h = 60 minutes. The initial value problem is

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

7 0

3 years ago

SAVE ME. Please Answer my Questions Clevers.

Vladimir [108]

Answer:

See below

Step-by-step explanation:

Q1. if a counting number is selected at random from a set of whole number less than or equal to 20 find the probability of getting:

Counting numbers are Natural numbers: $\mathbb{N}$

Also, we have Whole numbers. Despite not having an official symbol, I usually denote the set as $\mathbb{Z}_{\ge 0}$

Whole numbers less than or equal to 20: $A\leq 20, A \subset \mathbb{Z}_{\ge 0} \\\implies A=\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}$

A. Prime numbers

From the set A, the prime numbers are 2, 3, 5, 7, 11, 13, 17, 19.

Once we have 21 numbers in total and 8 prime numbers, the probability is:

$P=\frac{8}{21} \approx 40\%$

B. Composite numbers

From the set A, the composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20.

Once we have 21 numbers in total and 11 composite numbers, the probability is:

$P=\frac{11}{21} \approx 52\%$

C. Divisible by three

From the set A, the numbers divisible by three are 3, 6, 9, 12, 15, 18.

Once we have 21 numbers in total and 6 numbers divisible by three, the probability is:

$P=\frac{6}{21} \approx 30\%$

D. Square of 2

From the set A, the numbers square of 2 are 0, 1, 4, 9, 16.

$\sqrt{0} =0$

$\sqrt{1} =1$

$\sqrt{4} =2$

$\sqrt{9} =3$

$\sqrt{16} =4$

Once we have 21 numbers in total and 5 numbers square of 2 , the probability is:

$P=\frac{5}{21} \approx 24\%$

Q2. The opposite angle of acyclic quadrilaterals is in the ratio of 2:3. Find the degree measure of each opposite angle?

Once they're opposite, they add up to 180º

$2x+3x=180 \implies 5x=180 \implies x=36$

The first angle is 72º

The second angle is 108º

Q3. what is the solution set of 9x-4<13x-7 (domain, x e z) ?

$x \in \mathbb{Z}\\$

$x>\frac{3}{4}$

$x\in \left(\frac{3}{4},\infty \right)$

Q4. if three fourth of a number is one tenths, what is the number?

$\frac{3}{4} x =\frac{1}{10} \implies 3x=\frac{4}{10} \implies \boxed{x = \frac{2}{15}}$

Q5. which one is the equation of the line passing through the origin and having a slope 4?

$y=mx+b$

$m: \text{slope}$

$b: \text{y-intercept}$

B. Y= 4x

7 0

2 years ago

You have a credit card that has a balance of $3,589.90 and a credit limit of $5,000. If you have a good credit rating, how much

Maslowich

Answer:

maybe $1107.55

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Step-by-step explanation:

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3 years ago

In 2003, there were about 5.8078 X 10^8 people using the Internet in the world and about 1.6575 X 10^8 of these people were in t

lianna [129]

Answer:

28.5% Internet users in 2003 were in the United States.

Step-by-step explanation:

We are given the following in the question:

Number of people using the internet =

$5.8078 \times 10^8$

Number of people in United States =

$1.6575 \times 10^8$

Percent of Internet users in 2003 were in the United States =

$=\dfrac{\text{Number of users in United States}}{\text{Number of internet user in world}}\times 100\%\\\\=\dfrac{ 1.6575 \times 10^8}{5.8078 \times 10^8}\times 100\%\\\\=28.5\%$

Thus, 28.5% Internet users in 2003 were in the United States.

6 0

3 years ago