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2 years ago

How to solve 7+(-15)+12

2 answers:

8 0

7+(-15)+12
Adding a negative number is the same as simply subtracting it.
7-15+12
7 - 15 = negative 8 (use a number line)
-8 + 12 = 4 (use a number line)

makvit [3.9K]2 years ago

8 0

7 + (-15) + 12

First, simplify brackets. / Your problem should look like: 7 - 15 + 12.
Second, simplify. / Your problem should look like: 4.

Answer: 4

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Royal lawncare company produces and sells two packaged products

MrRa [10]

Royal Lawncare Company produces and sells two packaged products. Weedban and Greengrow. Revenue and cost information relating to the products follow: Product Weedban Greengrow Selling price per unit $ 11.00 $ 36.00 Variable expenses per unit $ 3.00 $ 14.00 Traceable fixed expenses per year $ 136.000 $ 31.000 Common fixed expenses in the company total $96.000 annually. Last year the company produced and sold 37.000 units of Weedban and 15.500 units of Greengrow. Required: Prepare a contribution format income statement segmented by product lines. Product Line Total Company Weedban Greengrow Sales Variable expenses Contribution margin Traceable fixed expenses Product line segment margin Common fixed expenses not traceable to products Net operating income

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2 years ago

Please help !!!!!!!!!

atroni [7]

Answer:

Katherine invested $12,000

Step-by-step explanation:

Use formula

$I=P\cdot r\cdot t,$

where

I = interest,

P = principal,

r = rate (as decimal),

t = time (in years).

In your case,

t = 1 year,

r = 0.06 (or 6%)

P + I =$12,720, thus

$12,720-P=P\cdot 0.06\cdot 1\\ \\12,720-P=0.06P\\ \\12,720=P+0.06P\\ \\1.06P=12,720\\ \\P=\dfrac{12,720}{1.06}\\ \\P=\$12,000\\ \\I=\$12,720-\$12,000=\$720$

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3 years ago

Find sin(7pie/4) using exact values

rewona [7]

$sin( \frac{ 7\pi }{4} )=-sin(2 \pi - \frac{ 7\pi }{4} )=-sin \frac{ \pi }{4} =- \frac{1}{ \sqrt{2} }$

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3 years ago

Which set of data contains two outliers?

wariber [46]

Answer:

D: 101, 135, 131, 99, 138, 136, 140

Step-by-step explanation:

edg2020 (do not get this confused with the question: "which set contains no outliers"

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2 years ago

Read 2 more answers

The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar

Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5%

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean debt ratio of Ohio banks = 6%

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 1.83%

n = sample of banks = 7

So, test statistics = $\frac{6-3.5}{\frac{1.83}{\sqrt{7} } }$ ~ $t_6$

= 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

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3 years ago