Answer:
x = 20
Step-by-step explanation:
The two angles are complementary angles, which means they add to 90 degrees
2x+7 + 43 = 90
Combine like terms
2x+50 = 90
Subtract 50 from each side
2x+50-50 = 90-50
2x = 40
Divide each side by 2
2x/2 = 40/2
x = 20
Answer:
343.77°
Step-by-step explanation:
1 radian =
°
6 radians will be;
6 ×
° =343.7746771
°
Or 343.77° (rounded up to nearest hundredth)
Answer:729
Step-by-step explanation:
81^3/2
(3^4)^3/2
3^6
729
The answer is D.
If the slope is -4/5 and the y int. is -1/6 then x is the slope.
Answer:

Step-by-step explanation:
Ok, so we start by setting the integral up. The integral we need to solve is:

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:
U=5+x
du=dx
x=U-5
so when substituting the integral will look like this:

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

so we must define p, q, p' and q':
p=ln U


q'=U-5
and now we plug these into the formula:

Which simplifies to:

Which solves to:

so we can substitute U back, so we get:

and now we can simplify:



notice how all the constants were combined into one big constant C.