Answer:
needd points
Step-by-step explanation:
thx
Answer:
hola puto
Step-by-step explanation:
bggyyhh yyesws kihtwrqas bts23e4gyhun
<span>distributive property
</span><span>B. −3⋅(6.48)=(−3⋅6)+(−3⋅0.4)+(−3⋅0.08) </span>
To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer:
4 & 17/20
Step-by-step explanation:
