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3 years ago

On a piece of paper, use a protractor to construct right triangle ABC with AB=3 in. , m∠A=90° , and m∠B=45° .

1 answer:

3 0

The best and most correct answer among the choices provided by the question is the fourth choice. The statement that is true about the triangle is "<span>AC=6 in." </span>I hope my answer has come to your help. God bless and have a nice day ahead!

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Excellent! Move on to the 7th (or 8th if you count 0)<br> Fibonacci number.

anygoal [31]

Answer:

sorry i dont know the answer to that i just need the points

Step-by-step explanation:

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4 years ago

Help please :). I hate trigonometry

elena-s [515]

Answer: You shouldn't hate trig.

Step-by-step explanation:

SinΘ= opposite/hypotenuse

SinΘ=y/x

Sin(16) = 9/x

x = 9/Sin(16)

x= 32.7 cm

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3 years ago

According to a study done by a university student, the probability a randomly selected individual will not cover his or her mou

Igoryamba

Answer: kindly check explanation

Step-by-step explanation:

Probability of not covering mouth = p(success) = 0.267

Hence, p(covering mouth) = 1 - 0.267 = 0.733

a) What is the probability that among 12 randomly observed individuals exactly 8 do not cover their mouth when sneezing?

Number of samples (n) = 12

P(X = 8)

Using binomial distribution :

P(x) = nCx * p^x * (1-p)^(n-x)

P(x =8) = 12C8 * 0.267^8 * 0.733^(12-8)

P(x =8) = 12C8 * 0.267^8 * 0.733^4

= 0.00369

b) What is the probability that among 12 randomly observed individuals fewer than 6 do not cover their mouth when sneezing?

P(X < 6) = p(5) + p(4) + p(3) + p(2) + p(1) + p(0)

To save computation time, we can use an online binomial probability calculator :

P(X < 6) = 0.9275

C.) Yes, I will be surprised, because from the binomial probability obtained above, there is a high probability (0.9275) that fewer than half do not cover their mouth.

5 0

4 years ago

What is the square root of 56

Evgen [1.6K]

Answer:

7.48331477355

Step-by-step explanation:

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3 years ago

A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting

Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees} = \frac{6}{15}$

b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant wins on first draw)

= $\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}$

= $\frac{\frac{5}{15} \times \frac{6}{14}}{\frac{5}{15} } = \frac{6}{14}$ .

The probability that a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw = $\frac{6}{15}$ is not true.

The probability that a secretary wins on the second draw = $\frac{number \hspace{0.1cm} of \hspace{0.1cm} secretaries \hspace{0.1cm} remaining } { number \hspace{0.1cm} of \hspace{0.1cm} employees \hspace{0.1cm} remaining} = \frac{6 - 1}{15 - 1} = \frac{5}{14}$

c.) The probability that a consultant wins on the first draw =

$\frac{number \hspace{0.1cm} of \hspace{0.1cm} consultants \hspace{0.1cm} } { number \hspace{0.1cm} of \hspace{0.1cm} employees \hspace{0.1cm} } = \frac{5 }{15} = \frac{1}{3}$

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= $\frac{6}{15} \times \frac{5}{14} = \frac{1}{7}$

Therefore the only statement that is not true is b.)

5 0

4 years ago