Question

The scope of a variable declared inside of a function is:

Answer 1

Answer:

a

Explanation:

The variable declared is local within that function that is the declared variable is accessible inside that block itself, it cannot be accessible outside the given function.

ex - void add()

{

int a=10,  b=20 , c ;

c = a + b ;

cout << c ;

}

int main()

{

cout << "value for c is :"<< c ;

return 0;

}

Here inside the add function variable a, b,c are declared and initialized inside the function.