Answer:
-29 and -12
Step-by-step explanation:
A+b+8 = 11-3c
a+b+3c = 11-8
a+b+3c = 3
a = b-1
c = b+1
b-1+b+3*(b+1) = 3
2b-b+3b+3 = 3
4b = 3-3
4b = 0
b = 0
a = b-1
a = 0-1
a = -1
c = b+1
c = 0+1
c = 1
a = -1, b = 0, c = 1
The length of side c would be 8.
Step-by-step explanation:
Given that,
a = 4
b = 6
cosC = -1/4
If we are given two sides and angle, the law of Cosines can be used to find the third side:
![c^{2} = a^{2} + b^{2} - 2ab (cos(c))](https://tex.z-dn.net/?f=c%5E%7B2%7D%20%3D%20a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20-%202ab%20%28cos%28c%29%29)
By inserting the values in the formula, we get
![c^{2} = 16 + 36 + 12](https://tex.z-dn.net/?f=c%5E%7B2%7D%20%3D%2016%20%2B%2036%20%2B%2012)
![c^{2} = 64](https://tex.z-dn.net/?f=c%5E%7B2%7D%20%3D%2064)
![\sqrt{c^{2} } = \sqrt{64}](https://tex.z-dn.net/?f=%5Csqrt%7Bc%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%7B64%7D)
c = 8.
Therefore, the length of side c would be 8.