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poizon [28]
3 years ago
11

PLEASEEEE answer!!!! NEED THIS TO GRADUATE

Mathematics
1 answer:
KengaRu [80]3 years ago
8 0

Answer:

number of students with blue eyes and blond hair= 42

Number of students with grey eyes and brown hair= 5

Difference of number of kids with grey eyes and brown hair and the number of students with green eyes and black hair =6

Difference of the number of students with green eyes and blond hair and the number of students with grey eyes= 14

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Choose the conditional statement that is equivalent to this sentence : "Tigers have stripes."
TiliK225 [7]

i think the answer is c, hope this helps ;)

3 0
2 years ago
Read 2 more answers
Ameer uses \dfrac14 4 1 ​ start fraction, 1, divided by, 4, end fraction of a bottle of shampoo to give each of his dogs a bath.
svet-max [94.6K]

Answer:

138 3/8

Step-by-step explanation:

total shampoo used for 555 dogs = 1/4 x 555 = 138 3/8 bottles

7 0
2 years ago
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} is your average rate of change,

Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
2 years ago
An automated assembly line produces 840 units per hour. At the same production rate, how many units could be produced in 45
WARRIOR [948]

Answer:

The 630

Step-by-step explanation:

i took the test on usa test prep

6 0
2 years ago
The national mean sales price for a new one-family home is $181,900. A sample of 40 one-family homes in the south showed a sampl
SIZIF [17.4K]

Answer:

a

The  null hypothesis is  \mu  =  \$181,900

The alternative hypothesis is  \mu <  \$ 181.900

b

t = -2.92

c

p-value  =  0.0016948

d

There no sufficient evidence to support the conclusion that the population mean sales prices for new one-family homes in the South is less expensive than the national mean of $181,900

Step-by-step explanation:

From the question we are told that

   The  population mean is  \mu  =  \$ 181, 900

    The  sample size is  n =  40

    The  sample  mean is  \=  x  =  \$ 166,400

      The  sample  standard deviation is s= \$ 33, 500

The  null hypothesis is  \mu  =  \$181,900

The alternative hypothesis is  \mu <  \$ 181.900

 

Generally the test statistics is mathematically represented as

      t =  \frac{ \= x  -  \mu }{ \frac{s}{\sqrt{n} } }

=>    t =  \frac{  166400  - 181900 }{ \frac{33500}{\sqrt{40} } }

=>    t = -2.92

Generally the p-value is obtain from the z-table  the value is  

      p-value  =  P(Z < t ) = P(Z  <  -2.93) = 0.0016948

=>    p-value  =  0.0016948

From the calculation we see that  

     p-value  >  \alpha  hence we fail to reject the null hypothesis

Thus there no sufficient evidence to support the conclusion that the population mean sales prices for new one-family homes in the South is less expensive than the national mean of $181,900

3 0
3 years ago
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