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3 years ago

PLEASEEEE answer!!!! NEED THIS TO GRADUATE

Mathematics

1 answer:

KengaRu [80]3 years ago

8 0

Answer:

number of students with blue eyes and blond hair= 42

Number of students with grey eyes and brown hair= 5

Difference of number of kids with grey eyes and brown hair and the number of students with green eyes and black hair =6

Difference of the number of students with green eyes and blond hair and the number of students with grey eyes= 14

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Choose the conditional statement that is equivalent to this sentence : "Tigers have stripes."

TiliK225 [7]

i think the answer is c, hope this helps ;)

3 0

2 years ago

Read 2 more answers

Ameer uses \dfrac14 4 1 start fraction, 1, divided by, 4, end fraction of a bottle of shampoo to give each of his dogs a bath.

svet-max [94.6K]

Answer:

138 3/8

Step-by-step explanation:

total shampoo used for 555 dogs = 1/4 x 555 = 138 3/8 bottles

7 0

2 years ago

If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.

galina1969 [7]

Answer:

$\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ is your average rate of change,

Step-by-step explanation:

average rate of change is

$\frac{f(a+h)-f(a)}{a+h-a}$ , by slope formula

simplify this to get $\frac{f(a+h)-f(a)}{h}$ , which is the definition of the derivative as h goes to 0

$\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}$

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

$\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}$

simplifying

$\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ (your average rate of change)

6 0

2 years ago

An automated assembly line produces 840 units per hour. At the same production rate, how many units could be produced in 45

WARRIOR [948]

Answer:

The 630

Step-by-step explanation:

i took the test on usa test prep

6 0

2 years ago

The national mean sales price for a new one-family home is $181,900. A sample of 40 one-family homes in the south showed a sampl

SIZIF [17.4K]

Answer:

The null hypothesis is $\mu = \$181,900$

The alternative hypothesis is $\mu < \$ 181.900$

$t = -2.92$

$p-value = 0.0016948$

There no sufficient evidence to support the conclusion that the population mean sales prices for new one-family homes in the South is less expensive than the national mean of $181,900

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = \$ 181, 900$

The sample size is $n = 40$

The sample mean is $\= x = \$ 166,400$

The sample standard deviation is $s= \$ 33, 500$

The null hypothesis is $\mu = \$181,900$

The alternative hypothesis is $\mu < \$ 181.900$

Generally the test statistics is mathematically represented as

$t = \frac{ \= x - \mu }{ \frac{s}{\sqrt{n} } }$

=> $t = \frac{ 166400 - 181900 }{ \frac{33500}{\sqrt{40} } }$

=> $t = -2.92$

Generally the p-value is obtain from the z-table the value is

$p-value = P(Z < t ) = P(Z < -2.93) = 0.0016948$

=> $p-value = 0.0016948$

From the calculation we see that

$p-value > \alpha$ hence we fail to reject the null hypothesis

Thus there no sufficient evidence to support the conclusion that the population mean sales prices for new one-family homes in the South is less expensive than the national mean of $181,900

3 0

3 years ago