Question

The Anderson family has 3 kids 3 boys and 0 girls suppose that for each birth the probability of a boy birthday is 1/2 and the probability of a girl birth is also 1/2 what is the fractional probility of having 3 boys and 0 girls ina family first 3 births

Answer 1

Answer:

Fractional probability of having 3 boys and 0 girls in a family for first 3 births is $\frac{1}{8}$.

Step-by-step explanation:

Let A be the event of birth of a boy.

Let B be the event of birth of a girl.

Probability of birth of a boy, P(A) $= \frac{1}{2}$

Probability of birth of a girl, P(B) $= \frac{1}{2}$

We have to find the probability of birth of 3 boys i.e. event A occurring 3 times in a succession. It is independent events i.e. do not have any dependency on occurrence of any event.

So, Required probability can be calculated just by multiplying P(A) for 3 times.

i.e.

$P(E) = P(A) \times P(A) \times P(A)\\\Rightarrow \dfrac{1}{2} \times \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow \dfrac{1}{8}$

So, the probability of having 3 boys and 0 girls in the family is $\frac{1}{8}$.