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2 years ago

5

Need help !! I would appreciate it !!

1 answer:

borishaifa [10]2 years ago

3 0

Answer:

sqrt(2^4) sqrt(5)

Step-by-step explanation:

sqrt(80)

sqrt(80) = sqrt(16*5)

We know that sqrt(ab) =sqrt(a) sqrt(b)

sqrt(16) sqrt(5)

sqrt(4*4) sqrt(5)

sqrt(2*2*2*2) sqrt(5)

sqrt(2^4) sqrt(5)

You might be interested in

If the area of the rectangle is 130 square inches then what is the rectangles height, h

fomenos

Answer:

130/l in where l is the length of the rectangle

Step-by-step explanation:

The formula for area of a rectangle is length by width where the width is the height of the rectangle

Given that area=130 in²

Lets assume the length of this rectangle is =l inches

Then ;

A=l*w

130 =l*w

130/l = w

130/l in = height

5 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

Paolo is adding the numbers below. what is the sum written in scientific notation?

jolli1 [7]

Where are your numbers?

8 0

3 years ago

Please answer this!) Name each angle in four ways. The classify as acute,right,obtuse or straight. When writings the name write

Rudik [331]

Answer:

B

Step-by-step explanation: ik it is

8 0

2 years ago

A deck of cards has a 5 pink, 2 gray, And 6 black cards. You pick two cards from the deck without replacement. What is the proba

Dahasolnce [82]

Answer:

<u>The probability that the first card is gray and the second card is pink= 5/78</u>

Step-by-step explanation:

A deck of cards has a 5 pink, 2 gray, And 6 black cards.

The total cards = 5 + 2 + 6 = 13

You pick two cards from the deck without replacement.

The probability that the first card is gray = 2/13

The remaining cards = 13 - 1 = 12

The probability that the second card is pink = 5/12

So,

The probability that the first card is gray and the second card is pink =

= 2/13 * 5/12 = 10/156 = 5/78

8 0

2 years ago

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