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2 years ago

Population in 2000 was 6.1 billion and increases at an annual rate of 1.4% estimate population in 2020

Mathematics

1 answer:

solong [7]2 years ago

6 0

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Decompose 3/8 as the sum of unit fractions

bearhunter [10]

Unit fractions are fractions with a 1 as the numerator(number on top)
so 3/8 equals 1/8+1/8+1/8

8 0

2 years ago

Rebeca spent $32.55 for a photo album and three identical candles. The photo album cost $17.50 and the sales tax was $1.55. How

Marina86 [1]

Answer: $4.50 per candle

Step-by-step explanation:

$32.55 - $17.50 - $1.55 = $13.50 for all the candles

To find the price of a single candle we divide our answer by 3

13.50/3 = $4.50

3 0

3 years ago

Two years ago, Paul bought $350 worth of stock in a cell phone company. Since then the value of his stock has been increasing at

zalisa [80]

Answer: $384.13 ( rounded)

Original number: $384.125

Step-by-step explanation:

Find 9.75% of Paul's original stock, to find out how much it increased.

9.75*350/100=34.125

Add $34.125 to his original stock.

$384.125

5 0

2 years ago

Draw a graph of a proportional relationship that passes through the point (2, 1).

Black_prince [1.1K]

Answer:

y=1/2x

Step-by-step explanation:

5 0

2 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers