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grin007 [14]
3 years ago
9

Distribute 6(c - 3)?

Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer: The blue diamond "6c-18"

Step-by-step explanation:

Because the 6 would distribute with the c, so 6c, then it would distribute with the 3, which would be 18, because 6x3=18. Then the equation becomes 6c-18

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What rule is this, please answer correctly, please
hichkok12 [17]

Answer:

Reflection

Step-by-step explanation: It is reflection because it is the same thing just reflected

7 0
2 years ago
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9= 2/3 (x+12) plz help
avanturin [10]

Answer:  x=3/2  

Step-by-step explanation:

Multiply the parentheses by 2/3.  9=2/3x+8.

Multiply  both sides by 3 .  27=2x+24

Move the term. When moved to the left side it changes from positive to a negative.  -2x=24-27.

-2x=-3

Divide both sides by -2

x=3/2   (x=1 1/2, x=1.5)

5 0
3 years ago
Jordan throws a ball from a cliff 12 feet above the ground with an initial velocity of 32 feet per second. In the following func
lbvjy [14]

Answer:

Your answer will be the third function

Step-by-step explanation:

The base function you need to know is h(t)= 1/2at^2

Your acceleration in this problem is going to be gravity which they give to you, 32 feet per second squared. Since the ball is falling, it means it will have negative acceleration. Now you have the equation h(t)= -16t^2. The final step is to add the initial height from which the ball was dropped giving you: h(t)= -16t^2 +12

8 0
2 years ago
For the function f(x) = |2x-7| - 3 find f(2)
olasank [31]
Evaluate abs(2 x - 7) - 3 where x = 2:abs(2 x - 7) - 3 = abs(2 2 - 7) - 3
2×2 = 4:abs(4 - 7) - 3
4 - 7 = -3:abs(-3) - 3
Since -3<=0, then abs(-3) = 3:3 - 3
3 - 3 = 0:Answer: 0
8 0
3 years ago
Read 2 more answers
Can you help me with this problem please
Over [174]

Remark

I think you want us to do both 3 and 4


Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.


RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long


TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.


Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.


Area = (b1 + b2)*h/2


Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7


Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5


Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS


<em>Area of the rectangle </em>= L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42


<em>Area of the triangle</em> = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5


Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0
3 years ago
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