The equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)
<h3>What is the equation of the ellipse represented in the graph?</h3>
Herein we have a representation of an ellipse in the image attached aside, ellipses are characterized by the following <em>standard</em> formula:
(x - h)² / a² + (y - k)² / b² = 1 (1)
Where:
- (h, k) - Coordinates of the center
- a, b - Lengths of the semiaxes
Please notice that ellipse will be vertical if b > a, otherwise it will be horizontal. The graph exhibits a <em>vertical</em> ellipse centered at the origin and therefore we conclude that (h, k) = (0, 0) and b > a (b = 10, a = 2). Finally, the equation that represents the graph of the ellipse is x² / 4 + y² / 100 = 1. (Correct choice: D)
To learn more on ellipses: brainly.com/question/14281133
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Answer: 2a - 10
Step-by-step explanation:
a represents the number of students in the art club.
The number of students in a school's math club is ten less than twice the number of students in the art club.
ten less = - 10
twice the number of students in the art club = 2*a
2a - 10 = the number of students in the math club
If the width is 15, and the scale factor from width to length is 3:2, then you will have to divide 15 by 3 to get your original width.
15/3 = 5.
5 is your original width.
Answer:
1. B) Figure B.
2. C) Figure C.
3. D) Figure D.
4. C) Figure C.
Step-by-step explanation:
Given: Radius of Circle A= 4
Radius of Circle B= 5
Radius of circle C= 6
Radius of circle D= 7
Now, finding circumference and area of all the circle.
We know, circumference of circle= 
Area of circle= 
Where, r= radius of circle and π = 3.14
First, solving for figure A
Circumference= 
Area= 
Solving for Figure B
Circumference= 
Area= 
Solving for Figure C
Circumference= 
Area= 
Solving for Figure D
Circumference= 
Area= 
∴ 1. Answer is Figure B.
2. Answer is figure C.
3. Answer is Figure D
4. Answer is Figure C.