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2 years ago

Free brainlest and 100 points have a nice day ;)

Mathematics

2 answers:

kramer2 years ago

8 0

Answer:

Thanks! I needed that since I am way behind on my schoolwork- hopefully I get free time today-

Step-by-step explanation:

I also need five more brainliest to be next level-

labwork [276]2 years ago

3 0

Omgggg thank youuuuu

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Write an equation to represent the sequence<br> 19, 38, 57, 76,95 ...

morpeh [17]

Answer:

Step-by-step explanation:

lets look at the numbers

38-19=19

57-38=19

76-57=19

aₙ=aₙ-₁ +19

8 0

2 years ago

Please help!

Mrrafil [7]

Answer:

$\sf C. \quad \dfrac{1}{9}$

Step-by-step explanation:

<u>Addition Law for Probability</u>

$\sf P(A \cup B)=P(A)+P(B)-P(A \cap B)$

Given:

$\sf P(A)=\dfrac{1}{3}=\dfrac{3}{9}$

$\sf P(B)=\dfrac{2}{9}$

$\sf P(A \cup B)=\dfrac{4}{9}$

Substitute the given values into the formula and solve for P(A ∩ B):

$\implies \sf P(A \cup B) = P(A)+P(B)-P(A \cap B)$

$\implies \sf \dfrac{4}{9} = \sf \dfrac{3}{9}+\dfrac{2}{9}-P(A \cap B)$

$\implies \sf P(A \cap B) = \sf \dfrac{3}{9}+\dfrac{2}{9}-\dfrac{4}{9}$

$\implies \sf P(A \cap B) = \sf \dfrac{3+2-4}{9}$

$\implies \sf P(A \cap B) = \sf \dfrac{1}{9}$

4 0

1 year ago

Read 2 more answers

-8p^2+8p+7=9<br> how do i find the discriminant

m_a_m_a [10]

The discriminant can be found using the formula b^2-4ac

First put your equation in standard form, where all your values are on one side, and just add f(x) or y in front of your equation.
y= 8p^2-8p+2

The first value of your equation is a (a=8)
The second term of your equation is b (b=-8)
The last term of your equation is c (c=2)

Plug in the values to the discriminant equation b^2-4ac

5 0

3 years ago

Can someone check my answers

Lelechka [254]

The first image with the answers are right but the second image is blank

8 0

3 years ago

Read 2 more answers

If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.

Triss [41]

(6y - 11)(6y + 11) = ay² - b |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b |add b to both sides

ay² = 36y² - 121 + b |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

$\boxed{a=\dfrac{36y^2-121+b}{y^2}}$

7 0

2 years ago