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kirza4 [7]
4 years ago
11

Find the equation of the line that contains the point (4, 5) and is perpendicular to the line y = (5/4)x − 3.

Mathematics
1 answer:
Reil [10]4 years ago
7 0
The product of the slopes of the perpendicular lines must equal -1. Let the unknown slope be m.
(5/4)m = -1
m = -(4/5)
The required equation is of the form:
y = -(4/5)x + b
Plugging in the coordinates of the given point, we get:
5 = -(16/5) + b
b = 8 1/5.
The required equation is therefore:
y = -(4/5)x + 8 1/5
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Step-by-step explanation:

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c. The additive inverse of a number x is another number y such that x+y=0. So, we're looking form a number such that 3+O=0, and thus O = - 3.

d. This point looks a bit ambiguous to me honestly. We know that IO = 2, which I presume means that the points I and O are two units apart, but we're not told if I is two units left or right with respect to O. To solve this issue, I'm assuming that IO implies that I sits before O, and so I is two units left with respect to O. As we said in point a., two units left means two less, so we have I = -3-2 = -5. At this point, point L is halfway between -5 and -3, and thus L = - 4.

e. The sum of the coordinates of A and E is 7 + 3 = 10. Half that sum is 5, so M = 5.

In the attached image, you can see the number line filled with the points asked by the exercise.

Second exercise:

All the requests can be written as an equation in which we look for the values of x. Below you find the equation and the solutions.

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Step-by-step explanation:

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