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2 years ago

What is the output of the following code?

Computers and Technology

1 answer:

Lynna [10]2 years ago

8 0

Answer:

The output is 24

Explanation:

Given

The above code segment

Required

The output

We have (on the first line):

$x = 6$

$y = 3$

$z=24$

$result=0$

On the second line:

$result = 2*((z/(x-y))\%y+10)$

Substitute the value of each variable

$result = 2*((24/(6-3))\%3+10)$

Solve the inner brackets

$result = 2*((24/3)\%3+10)$

$result = 2*(8\%3+10)$

8%3 implies that, the remainder when 8 is divided by 3.

The remainder is 2

So:

$result = 2*(2+10)$

$result = 2*12$

$result = 24$

Hence, the output is 24

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The program in Python is as follows:

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

num = input("Decimal: ")

BCDValue = ""

valid = True

for i in range(len(num)):

if num[i].isdigit():

if(int(num[i])>= 0 and int(num[i])<8):

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else:

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break;

else:

valid = False

break;

if(valid):

print(BCDValue)

else:

print("Invalid")

Explanation:

This initializes the BCD corresponding value of the decimal number to a list

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

This gets input for a decimal number

num = input("Decimal: ")

This initializes the required output (i.e. BCD value) to an empty string

BCDValue = ""

This initializes valid input to True (Boolean)

valid = True

This iterates through the input string

for i in range(len(num)):

This checks if each character of the string is a number

if num[i].isdigit():

If yes, it checks if the number ranges from 0 to 7 (inclusive)

if(int(num[i])>= 0 and int(num[i])<8):

If yes, the corresponding BCD value is calculated

BCDValue += BCD[i]+" "

else:

If otherwise, then the input string is invalid and the loop is exited

valid = False

break;

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else:

valid = False

break;

If valid is True, then the BCD value is printed

if(valid):

print(BCDValue)

If otherwise, it prints Invalid

else:

print("Invalid")

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3 years ago