Answer:
TU = 6
Step-by-step explanation:
Using the Segment Addition Postulate, we know that TU + UV = TV, and since UV = 6 and TV = 12, we know that TU + 6 = 12, therefore, TU = 6.
Log 2 over 3 = 0.10034333188
Given:
Polynomials
To find:
Monomial of 2nd degree with leading coefficient 3
Solution:
Monomial is an algebraic expression with only one term.
Option A: 
It is not a monomial because it have 2 terms.
It is not true.
Option B:
It is not a monomial because it have 2 terms.
It is not true.
Option C: 
It have one term only. So, it is a monomial.
Degree means highest power. So degree = 2
Leading coefficient means the value before variable.
Leading coefficient = 3
It is true.
Option D: 
It have one term only. So, it is a monomial.
Degree means highest power. So degree = 3
It is not true.
Therefore
is a monomial of 2nd degree with a leading coefficient of 3.
Answer:
We can find the individual probabilities:
And replacing we got:
![P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%205%29%20%3D%201-%5B0.00114%2B0.009282%2B0.0358%2B0.0869%2B0.149%5D%3D%200.7178)
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
And we want to find this probability:

And we can use the complement rule:
We can find the individual probabilities:
And replacing we got:
![P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%205%29%20%3D%201-%5B0.00114%2B0.009282%2B0.0358%2B0.0869%2B0.149%5D%3D%200.7178)