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Dafna11 [192]
2 years ago
13

What is the discrimination of 5x-10x+5=0

Mathematics
1 answer:
liberstina [14]2 years ago
8 0

Answer:

x=1

Step-by-step explanation:

Trust me

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Select the equation in which the graph of the line has a negative slope, and the y-intercept equals 10. Answer 10x + 5y = –25 5x
adoni [48]
The answer is 20x + 5y = 50
If u move the 20x over u get:
5y=-20x + 50

Solve for y by divided by 5

This gets y=-4x + 10

Now the answer is in slope intercept form: the -4 is the slope and 10 is the y-intercept
4 0
3 years ago
Without drawing the graph of the equation answer the question. How many points does the given equation have in common with the x
Alexandra [31]

Answer:

There are two points common with the x-axis

The vertex is under the x-axis by 24 units at x = 6

Step-by-step explanation:

* For the quadratic equation y = ax² + bx + c

- The roots of the equation are the intersection point between

  the equation and the x-axis ⇒ y = 0

- To find these roots we factorize the equation into two factors

  and equate each factor with zero

- The graph of the quadratic equation is called parabola,

 the parabola has vertex point. If the vertex point is (h , k)

∴ h = -b/2a, where b is the coefficient of x and is the coefficient of x²

∴ k = y where x = h

* Lets solve the problem

∵ y = x² - 12x + 12

- The formula to find the values of x when y = 0 is

 x=\frac{-b+\sqrt{b^{2}-4ac}}{2a},x=\frac{-b-\sqrt{b^{2}-4ac}}{2a}

∵ a = 1 , b = -12 , c = 12

∴ x=\frac{-(-12)+\sqrt{(-12)^{2}-4(1)(12)}}{2(1)}=\frac{12+\sqrt{144-48}}{2}

∴ x=\frac{12+\sqrt{96}}{2}=\frac{12+4\sqrt{6}}{2}=6+2\sqrt{6}

∴ The two roots are 6 + 2√6 and 6 - 2√6

* There are two points common with the x-axis

* Lets calculate the vertex

∵ h = -b/2a

∵ b = -12 and a = 1

∴ h =-(-12)/2(1) = 12/2 = 6

∴ k = (6²) - 12(6) + 12 = 36 - 72 + 12 = -24

∴ The vertex is (6 , -24)

* That means the vertex is under the x-axis by 24 units at x = 6

5 0
3 years ago
Geometry distance formula
viktelen [127]

A(-4, 2) and B(3, -2).

I will do number 2.

Let d(A, B) = distance between the two points.

d(A, B) = sqrt{(3 -(-4))^2 + (-2-2)^2}

d(A, B) = sqrt{(3 + 4))^2 + (-2-2)^2}

d(A, B) = sqrt{(7)^2 + (-4)^2}

d(A, B) = sqrt{49 + 16}

d(A, B) = sqrt{65}

Done!

8 0
3 years ago
If 13 out of 20 students are girls, what is the ratio<br> of girls to boys?
STALIN [3.7K]

Answer:

I think its 13:7

Step-by-step explanation:

3 0
2 years ago
If the point (x, square root 3/2) is on the unit circle, what is x?
photoshop1234 [79]

Answer:

\frac{1}{2}

Step-by-step explanation:

On a unit circle, the only points where y = \frac{\sqrt{3} }{2} have an x coordinate of \frac{1}{2} or \frac{-1}{2} . Since only one of those is an option, the answer is \frac{1}{2}.

5 0
3 years ago
Read 2 more answers
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