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topjm [15]
3 years ago
14

Three consecutive integers have a sum of 78. find the inte

Mathematics
2 answers:
VMariaS [17]3 years ago
5 0
Let the 3 numbers be x,x+1,x+2
Given sum of those 3 consecutive integers are 78
X+x+1+x+2=78
3x+3=78
3(x+1)=78
X+1=26
X=26-1
X=25

Therefore the numbers are 25,26,27
zalisa [80]3 years ago
3 0

Answer: 25, 26, and 27

Step-by-step explanation: Three consecutive integers can be represented as followed. Let's use "T" as our variable.

T → first integer

T + 1 → second integer

T + 2 → third integer

Since the sum of our three consecutive integers is 78, our equation will be as followed.

T + T + 1 + T + 2 = 78

We can simplify on the left.

3t + 3 = 78

     -3    -3   ← subtract 3 on both sides

     3t = 75

    ÷3    ÷3   ← divide by 3 on both sides

T = 25

T + 1 = 26

T + 2 = 27

Therefore, our three consecutive integers are 25, 26, and 27.

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Answer:

Zeros of the given function are x=5 and x=-1.

Step-by-step explanation:


f(x)=x^2-4x-5

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To find zeros, we need to set f(x)=0

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Hence zeros of the given function are x=5 and x=-1.


We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.

That will give the final graph as attached below:

for x=0,

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f(0)=0-0-5

f(0)=-5

Hence first point is (0,-5)

Similarly we can find more points.


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