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Vlada [557]
3 years ago
5

Calculate the density of a solid with the following data:

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0
It would be c.8.6291036592g/ml
Viefleur [7K]3 years ago
4 0

Answer:

d.8.63 g/ml

Step-by-step explanation:

Hello

In physics the density is a scalar magnitude referred to the amount of mass in a given volume of a substance or a solid object.it is given by:

density =\frac{mass\ of\ the\ object}{volume\ of\ the\ object} \\

Step 1

Find the volume of the object

According to the question

(Eq1)Volume of water=48.4 ml.

(Eq2)Volume of water+volume of the solid=62.7 ml

(Eq3)Mass of the object = 123.4 g

Now, from (Eq2) find volume of the solid

(Eq2)Volume of water+volume of the solid=62.7 ml

subtract volume of water on both sides

Volume of water+volume of the solid-Volume of water=62.7 ml-Volume of water

hence

(Eq4)volume of the solid=62.7 ml-Volume of water

Now, put (Eq1) into (Eq4)

volume of the solid=62.7 ml-48.4 ml

volume of the solid=14.3 ml

Step 2

put the values into the equation

density =\frac{mass\ of\ the\ object}{volume\ of\ the\ object} \\d=\frac{123.4 \ g}{14.3 \ ml} \\d=8.62937 \frac{g}{ml} \\ approximates\\d=8.63 g/ml

d=8.63 g/ml

in fact, answer b is not wrong since

1 ml=1 cm^{3}

Have a good day

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If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
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Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

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cos²α=1/(1+tg²α)

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Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
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