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kykrilka [37]
3 years ago
5

Circle D is below what is the arc measure of BC in degrees

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

84°

Step-by-step explanation:

\because (13n - 16) \degree + (7n  + 12) \degree + (6n)\degree \\= 360\degree \\  \\  \therefore \: (26n - 4) \degree= 360\degree \\  \\  \therefore \: 26n - 4= 360 \\  \\ \therefore \: 26n = 360 + 4 \\  \\ \therefore \: 26n = 364 \\  \\ \therefore \: n =  \frac{364}{26}  \\  \\ \therefore \: n =  14 \\  \\\because  m\overset { \frown}{BC} = (6n)°\\  \\\therefore \:m \overset { \frown}{BC} =(6\times 14)°  \\  \\   \huge \purple {\boxed {\therefore \:m\overset { \frown}{BC}= 84°}} \\

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Through (2,2) slope 3/2
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Step-by-step explanation:

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4 0
2 years ago
Find
Sedaia [141]

Answer:

The amount of steel used = 94.38 m^{2}

Step-by-step explanation:

Height of the tank = 4.5 m.

Diameter of the tank = 4.2 m.

But,

radius = \frac{diameter}{2}

           = \frac{4.2}{2}

radius  = 2.1 m

Total surface area of a cylinder = 2\pirh + 2\pir^{2}

                                      = 2\pir(r + h)

                                      = 2 x \frac{22}{7} x 2.1 (2.1 + 4.5)

                                      = 44 x 0.3 (6.6)

                                      = 87.12

Total surface area of a cylinder = 87.12 m^{2}

Since \frac{1}{12} of the steel was wasted, then;

\frac{1}{12} x 87.12 = 7.26 m^{2}

Actual area of steel sheet used = 87.12 + 7.26

                                                     = 94.38 m^{2}

Thus, 94.38 m^{2} of steel was used in making the tank.

4 0
2 years ago
CAN SOMEbody please help me
tensa zangetsu [6.8K]
Https://www.calculatorsoup.com/calculators/geometry-solids/surfacearea.php
use this calculator it’s super helpful with lots of these kinds of questions!
4 0
2 years ago
PLEASE HELP ME WITH THESE FOUR QUESTIONS TYSMMM!!! THANK YOU
Dima020 [189]

Answer:

107^\circ, 133^\circ, 20^\circ, \text{and}, 23^\circ

Step-by-step explanation:

9. For the lines 'm' and 'n' to be parallel the sum of interior angles should be 180 degrees that is:

x+73^\circ=180^\circ

x=107^\circ

10. For the lines  'm' and 'n' to be parallel the alternate exterior angles should be equal that is:

147^\circ=x+14^\circ

x=147^\circ-14^\circ

x=133^\circ

11. For the lines  'm' and 'n' to be parallel alternate angles should be equal that is:

180^\circ-3x=2x+20^\circ

Solving for 'x' we get:

180^\circ-20^\circ=3x+2x

5x=160^\circ

x=32^\circ

12. For the lines  'm' and 'n' to be parallel corresponding angles should be equal that is:

(7x-11)^\circ=(4x+58)^\circ

7x-4x=58^\circ+11^\circ

3x=69^\circ

x=\frac{69}{3}=23^\circ

8 0
3 years ago
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