Y = mx + b
1.) -6x + y = 4
Move variable x over to the other side by adding 6x.
y = 6x + 4
2.) -y - 2x = 4
Move variable x over to the other side by adding 2x.
-y = 2x + 4
Divide the whole thing by -1 because y needs to be positive and alone.
y = -2x - 4
Answer:
It has one solution
Step-by-step explanation:
![14x + 12] = 0\\\\14x+12=0\\\mathrm{Subtract\:}12\mathrm{\:from\:both\:sides}\\14x+12-12=0-12\\\\Simplify\\14x=-12\\\\\mathrm{Divide\:both\:sides\:by\:}14\\\frac{14x}{14}=\frac{-12}{14}\\\\Simplify\\x=-\frac{6}{7}](https://tex.z-dn.net/?f=14x%20%2B%2012%5D%20%3D%200%5C%5C%5C%5C14x%2B12%3D0%5C%5C%5Cmathrm%7BSubtract%5C%3A%7D12%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D%5C%5C14x%2B12-12%3D0-12%5C%5C%5C%5CSimplify%5C%5C14x%3D-12%5C%5C%5C%5C%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D14%5C%5C%5Cfrac%7B14x%7D%7B14%7D%3D%5Cfrac%7B-12%7D%7B14%7D%5C%5C%5C%5CSimplify%5C%5Cx%3D-%5Cfrac%7B6%7D%7B7%7D)
We must assume that he must put a whole number of objects in each wreath so we must find the greatest common factor
60=2 time 2 times 3 times 5
36=2 times 2 times 3 times 3
48=2 times 2 times 2 times 2 times 3
the factors are 2 times 2 times 3 or 12
there can be 12 wreath max
we total them up and divide by 12
60+36+48=144
144/12=12
12 items per wreath
Answer: don't know sorry
Step-by-step explanation:
Answer:
It's D
Step-by-step explanation:
