Answer:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Step-by-step explanation:
Correct statement is:
<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>
From Linear Algebra we get that dilation of a point with respect to another point is represented by:
(Eq. 1)
Where:
- Reference point with respect to origin, dimensionless.
- Original point with respect to origin, dimensionless.
- Dilation factor, dimensionless.
If we know that , and , then the coordinates of the image of the original point is:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Answer:
1) C) sin(θ) = 119/169
2) D) cos(θ) = 120/169
Step-by-step explanation:
The mnemonic SOH CAH TOA expresses the relationships you need for answering these questions.
Sin(θ) = Opposite/Hypotenuse = 119/169 . . . . . problem 1
Cos(θ) = Adjacent/Hypotenuse = 120/169 . . . . problem 2
<span>A system of equations has infinitely many solutions when the two
lines representing the equations coincide. i.e. the two equations are
the same or a multiple of each other.
2y - 4x = 6
2y = 4x + 6
2y = 2(2x + 3)
y = 2x + 3
-y = -(2x + 3)
-y = -2x - 3
Hence the other equation is -y = -2x - 3</span>
Answer:
This has one real solution, x=4
Step-by-step explanation:
8 - 4x = 0
Add 4x to each side
8 - 4x+4x = 0+4x
8 =4x
Divide each side by 4
8/4 = 4x/4
2 =x
This has one real solution, x=4
Account balance is $123.08
Step-by-step explanation:
- Step 1: Balance in Thompson's account = $283.12. Calculate the total amount of checks Thompson wrote in the month.
Total amount of checks = $23.09 + $7.56 + $125.11 + $4.28
= $160.04
- Step 2: Calculate his balance.
Account balance = $283.12 - $160.04
= $123.08