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4 years ago

A tangent to the curve y=6x-x² cuts the x axis at point P. Find the coordinates of P. Help me calc the coordinates please

Mathematics

1 answer:

Ilya [14]4 years ago

6 0

We know that the line is tangent at the point (2,8)

The derivative of the function at x=2 is

$f'(x) = 6-2x \implies f'(2) = 6-4=2$

So, the tangent line passes through the point (2,8) and has slope 2. The equation is

$y-8 = 2(x-2) \iff y = 2x+4$

This line crosses the x axis where y=0:

$0 = 2x+4 \iff 2x = -4 \iff x = -2$

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4 years ago

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3 years ago

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Brrunno [24]

Answer:

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Step-by-step explanation:

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4 years ago

A tangent to the curve y=6x-x² cuts the x axis at point P. Find the coordinates of P. Help me calc the coordinates please​

A tangent to the curve y=6x-x² cuts the x axis at point P. Find the coordinates of P. Help me calc the coordinates please