A tangent to the curve y=6x-x² cuts the x axis at point P. Find the coordinates of P. Help me calc the coordinates please
1 answer:
We know that the line is tangent at the point (2,8)
The derivative of the function at x=2 is

So, the tangent line passes through the point (2,8) and has slope 2. The equation is

This line crosses the x axis where y=0:

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Answer:
B negative
Step-by-step explanation:
use real numbers?
n is +9
m is -11
m/n * (-m*n^2)
-11/9 * (11*81)
-11/1 * (11*9)
-11 * 99
-1089
Answer:
-3
Step-by-step explanation:
y=mx+b
Answer:
x = 60°
Step-by-step explanation:
See picture below. When two parallel lines are cut by a transversal there are some special relationships.
Answer:
123
Step-by-step explanation:
s=-2
-15s^2-9(-5+s)
=-15s^2+45-9s
=-15s^2-9s+45
=15(-2)^2-9×(-2)+45
=15×4+18+45
=60+18+45
=123