Answer:
B) The maximum y-value of f(x) approaches 2
C) g(x) has the largest possible y-value
Step-by-step explanation:
f(x)=-5^x+2
f(x) is an exponential function.
Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞
Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→
Lim x→ -∞ f(x) = 2
Then the maximun y-value of f(x) approaches 2
g(x)=-5x^2+2
g(x) is a quadratic function. The graph is a parabola
g(x)=ax^2+bx+c
a=-5<0, the parabola opens downward and has a maximum value at
x=-b/(2a)
b=0
c=2
x=-0/2(-5)
x=0/10
x=0
The maximum value is at x=0:
g(0)=-5(0)^2+2=-5(0)+2=0+2→g(0)=2
The maximum value of g(x) is 2
Answer:
5,800m
Step-by-step explanation:
1 km = 1000 m
Use the SBD (small to big, divide) and BSM (big to small, multiply) method.
So, 5.8 X 1000, as we are converting km(big) to m(small) and move the decimal point corresponding to the number of zeroes = 5800m
When I look at a problem like this, I think of the FOIL method. This method states "You multiply integers in the order of First, Outside, Inside, Last, and then add them together"
(a -3b)(2a - 5b)
First --- 2a * a
Out --- (-5b) * a
In --- (-3b) * 2a
Last --- (-3b) * (-5b)
2a² - 5ab -6ab + 15b²
2a² - ab + 15b²
This would be your answer in simplest form!
Answer:y=-0.75x-1
Step-by-step explanation:firstly find gradient then use one coordinate and substitute for x and y to get the y intercept (c)
