(√3 - <em>i </em>) / (√3 + <em>i</em> ) × (√3 - <em>i</em> ) / (√3 - <em>i</em> ) = (√3 - <em>i</em> )² / ((√3)² - <em>i</em> ²)
… = ((√3)² - 2√3 <em>i</em> + <em>i</em> ²) / (3 - <em>i</em> ²)
… = (3 - 2√3 <em>i</em> - 1) / (3 - (-1))
… = (2 - 2√3 <em>i</em> ) / 4
… = 1/2 - √3/2 <em>i</em>
… = √((1/2)² + (-√3/2)²) exp(<em>i</em> arctan((-√3/2)/(1/2))
… = exp(<em>i</em> arctan(-√3))
… = exp(-<em>i</em> arctan(√3))
… = exp(-<em>iπ</em>/3)
By DeMoivre's theorem,
[(√3 - <em>i </em>) / (√3 + <em>i</em> )]⁶ = exp(-6<em>iπ</em>/3) = exp(-2<em>iπ</em>) = 1
Answer:
C) 11703
Step-by-step explanation:
from 1900 to 1976 is 76 years.
substitute 76 for t:
S = 2(76)^2 + 2(76) - 1
S = 2(5776) + 152 - 1
S = 11552 + 151
S = 11703
D T S
|-------27---------|
|------------35-----------|
DS=27+35=62
the answer is 62
Here is the set up:
Side 1 is 4x.
Side 2 is 5x + 3
Side 3 is 5x + 1
The perimeter is 102.
Perimeter = side 1 + side 2 + side 3
102 = 4x + 5x + 3 + 5x + 1
102 = 14x + 4
Take it from here.
