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Norma-Jean [14]
3 years ago
7

Find the 37th term of 27, 19, 11​

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

Answer:

291

Step-by-step explanation:

37=11+(37-1)*8

37 is the term you want

11 is the first term from least to greatest

(37-1) is from the term you want minus 1

*8 because 8 is the difference between each term

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Find the value of x and the value of y.
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I have 31 stamps in total. I have 4 more 1 cent stamps than 8 cent stamps and twice as many one cent stamps as 12 cent stamps. I
Neko [114]

Answer:

There area 14 one cent stamps

Step-by-step explanation:

Let

x -----> the number of 1 cent stamps

y -----> the number of 8 cent stamps

z -----> the number of 12 cent stamps

we know that

0.01x+0.08y+0.12z=1.78 -------> equation A

x=y+4 ------> y=x-4 -----> equation B

x=2z -----> z=0.5x ------> equation C

substitute equation B and equation C in equation A and solve for x

0.01x+0.08(x-4)+0.12(0.5x)=1.78

0.01x+0.08x-0.32+0.06x=1.78

0.15x=1.78 +0.32

0.15x=2.10

x=14

therefore

There area 14 one cent stamps

6 0
3 years ago
How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?
Allushta [10]
This is 6P4
the number of permutations of 4 from 6.  6! / 2!

= 6*5*4*3* 2 /  2 = 360
4 0
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