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3 years ago

HELP MEEEEEEE please

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

Answer:

scale factor = $\frac{1}{3}$

Step-by-step explanation:

Consider the ratio of corresponding sides, image to original, that is

scale factor = $\frac{T'V'}{TV}$ = $\frac{2}{6}$ = $\frac{1}{3}$

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A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago

Which statement comparing x² + 10 and x + x + x is true when x=−5 ?

Lina20 [59]

X^2 + 10 = 35 when x = -5
x + x + x = 3x = -15 when x = -5.

The answer is B because part A just restates the first equation, and Part C determines which is greater. If you want to determine the difference between the two when x = -5, part B is the best answer because it subtracts the product of one of them from the other.

3 0

3 years ago

PLEASEEE HELPPPP ASAPPPP

stellarik [79]

$\cos 27^{\circ} = \dfrac{KL}x\\\\\implies \cos 27^{\circ} = \dfrac{6.3}x\\\\\implies x = \dfrac{6.3}{\cos 27^{\circ}}=7.1~ \text{units.}$

6 0

2 years ago

Find the solution by elimination method. <br>Please Help.

love history [14]

Answer:

I'm newbie here

Step-by-step explanation:

Elimination Method.

4x + 6/y = 15 → step 1

6x - 8/y = 14 → step 2

so,

4x + 6/y = 15 |×6|

6x - 8/y = 14 |×4|

24x + 6/y(6) = 90

24x - 8/y(4) = 56

24x + 36/y = 90

24x - 32/y = 56

____________ _

68/y = 34

68 = 34y

34y = 68

y = 2

subsitution y = 2 to..

4x + 6/y = 15

4x + 6/2 = 15

4x + 3 = 15

4x = 12

x = 3

So, for x is 3, and for y is 2

5 0

3 years ago

Read 2 more answers

Given f(x)=9-2x, if f(x)=19, find the value of x. Can some one help please?

eimsori [14]

Answer: -5

Step-by-step explanation: 19 -9 = 10. 10/-2 = -5

6 0

4 years ago

Read 2 more answers