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Sphinxa [80]
3 years ago
9

??? quadrilateral abcd ??? is inscribed in this circle. what is the measure of angle c? enter your answer in the box. ?? a quadr

ilateral inscribed in a circle. the vertices of the quadrilateral lie on the edge of the circle and are labeled as a, b, c,
d. the interior angle a is labeled as left parenthesis 2 x plus 3 right parenthesis degrees. the angle b is labeled as left parenthesis 2 x minus 4 right parenthesis degrees. the angle d is labeled as left parenthesis 3 x plus 9 right parenthesis degrees.

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0
Answer: The measure of angle C is 107 degrees.

When, you have a quadrilateral inscribed in a circle, measure of the opposites sides are supplementary (they add to 180). Therefore, we can write and solve the following equation with angles D and B to find the value of x in the problem.

3x + 9 + 2x - 4 = 180
5x + 5 = 180
5x = 175
x = 35

Now, input x = 35 into the expression for A to find that the measure of angle A is 73.

Since A and C are supplementary:
A + C = 180 
73 + C = 180
C = 107
jeka57 [31]3 years ago
5 0

Answer:

∠C = 107°

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle, and a quadrilateral inscribed in a circle is known as cyclic quadrilateral.

So, ABCD is cyclic quadrilateral.

∠A = 2x + 3

∠B = 2x - 4

∠D = 3x + 9

Also. the sum of opposite angles of the cyclic quadrilateral is supplementary.

⇒ ∠B + ∠D = 180

⇒ 2x - 4 + 3x + 9 = 180

⇒ 5x = 175

⇒ x = 35

Now, ∠A = 73

Also, ∠A + ∠C = 180

⇒ ∠C = 180 - 73

⇒ ∠C = 107°

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Andrei [34K]

Answer:

2x^2 = 6x - 5.

-x^2 - 10x = 34.

These have only complex roots/

Step-by-step explanation:

3x^2 - 5x = -8

3x^2 - 5x + 8 = 0

There are complex roots if the discriminant  9b^2 - 4ac) is negative.

Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160

This is positive so the roots are real.

2x^2 = 6x - 5

2x^2 - 6x + 5 = 0

D = (-6)^2 - 4*2*5 =  36 - 40 = -4

So this has no real roots only complex ones.

12x = 9x^2 + 4

9x^2 - 12x + 4 = 0

D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.

- Real roots.

-x^2 - 10x = 34

x^2 + 10x + 34 = 0

D = (10)^2 - 4*1*34 = 100 - 136 = -36.

No real roots = only complex roots.

7 0
3 years ago
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atroni [7]

Answer:

the top one

Step-by-step explanation:

the only y one with negative 2

3 0
3 years ago
Use the sample data and confidence level given below to complete parts a through d.
Sholpan [36]

Answer:

Step-by-step explanation:

Given that a research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=1096 and x=542 who said yes.

i.e. sample size = n=1096\\

who said yes =x=542\\

Sample proportion = p=\frac{542}{1096} =0.4945

Std error of proportion = \sqrt{\frac{p(1-p)}{n} } \\=\sqrt{\frac{0.4945(1-0.4945)}{1096} } \\=0.0151

Margin of error 95% = 1.96 (se)\\=0.0296

Hence confidence interval for proportions

=(0.4945-0.0296, 0.4945+0.0296)\\= (0.4649,0.5241)

a) Point estimate =0.4945

B) Margin of error = 0.0296

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D) We are 95% confident that for large random samples representing the population, the proportion of yes will lie between these two values.

4 0
3 years ago
What is 3x+1? They say its really easy and I don't know how.
posledela

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{x = - 1 / 3}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{3x + 1}

Find: \textsf{The value of the unknown variable x}

Solution: In order to solve for x we need to isolate it with the first step being to subtract 1 from both sides and then we would divide both sides by 3 to give us the solution.

<u>Subtract 1 from both sides</u>

  • \textsf{3x + 1 = 0}
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<u>Divide both sides by 3</u>

  • \textsf{3x / 3 = - 1 / 3}
  • \textsf{x = - 1 / 3}

Therefore, the final answer would be that x is equal to -1/3.

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2 years ago
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Answer:

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{:}\longrightarrow\sf {\dfrac {1}{{\cancel{2}}}}\times {\dfrac{{\cancel {4}}}{3}}

{:}\longrightarrow\sf {\dfrac {2}{3}}

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3 years ago
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