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skelet666 [1.2K]
3 years ago
10

Solve for j.

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

( J - 6 ) × (J + 6 )

Step-by-step explanation:

j^2 -6^2

( J - 6 ) × ( j + 6 )

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Multiply the following 11 x square Y and 2 x square y square
yaroslaw [1]

Answer:

22 x^4y^3

Step-by-step explanation:

11x^2y\times 2x^2y^2\\

by multiplying

=11 \times 2 \times x^2 \timesx^2 \times y \times \times y^2\\=22 \times x^{2+2}y^{1+2}\\=22 x^4y^3

3 0
3 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
Zepler [3.9K]

Answer:

C. 0

Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac  if >0 we have 2 real solutions

                                                   =0  we have 1 real solutions

                                                   <0 we have 2 imaginary solutions

a = -4, b =3  c = -28

b^2 -4ac

(3)^2 - 4(-4)*(-28)

9 - 16(28)

9 -448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions

5 0
3 years ago
Help me with this!!!!!!!!!
Over [174]

Step-by-step explanation:

d = √(x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2

P1(0, 0, 0) P2(-6, 8, 3)

Substitute the values in the above equation and you will get

d = √(-6 - 0)^2 + (8 - 0)^2 + (3 - 0)^2

= √(36 + 64 + 9)

= √109

= 10.44

6 0
2 years ago
Read 2 more answers
Are the expressions (-2)^4 and -2^4 equivalent? Explain how you know.
Elden [556K]
No, becasue of PEMDAS
so parenthasees first
exponents next
mulitplciation next

(-2)^4=-2 times -2 times -2 times -2=positive number since even number of negative signs

-2^4=-1 times 2^2=-1 times 2 times 2 times 2 times 2=negative number since odd number of negative signs
3 0
3 years ago
Read 2 more answers
15,000,015,969+5,000,003
Nat2105 [25]
<h2>Answer:</h2><h2>15,005,015,972</h2><h2></h2><h2>Hope this helps!!</h2>
7 0
2 years ago
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