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3 years ago

Solve for j.

Mathematics

1 answer:

gavmur [86]3 years ago

5 0

Answer:

( J - 6 ) × (J + 6 )

Step-by-step explanation:

j^2 -6^2

( J - 6 ) × ( j + 6 )

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Deisha can build a fence in 15 hours, and Travis can build a fence in 12 hours. How long will it take them together to build a f

Basile [38]

Answer:

6 $\frac{2}{3}$

Step-by-step explanation:

Deisha's build rate = 1 fence per 15 hours = 1/15 fences per hour

Travis's build rate = 1 fence per 12 hours = 1/12 fences per hour

Working together, their combined rate is 1/15 + 1/12 = 3/20 fences per hour

So it takes them 20/3 = 6 2/3 hours per fence

6 0

2 years ago

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

3 years ago

If f(x) = 2x and g(x) = 5x + 2, what is (f + g)(x) when x = 3?

Minchanka [31]

Answer:

f÷g=2x+5x+2=7x+2

x=3

7×3+2=21+2=23

8 0

2 years ago

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Solve by elimination. 2x+5y=-1 <br> x+2y=0

vazorg [7]

Answer:

2x+5y+1=0

y= $\frac{1}{2} x$

Step-by-step explanation:

3 0

3 years ago

23=4w_13 simply your as much as possible

Nataly_w [17]

23=4w-13
First add 13 to both sides.
36=4w
w=9
Hope this helps!

5 0

3 years ago

Read 2 more answers