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3 years ago

What is the slope of the line passing through the points (0, 4) and (−8, −1) ?

Mathematics

1 answer:

dedylja [7]3 years ago

3 0

Answer: The slope of a line is m=(y2-y1)/(x2-x1) where (x1,y1) and (x2,y2) are the two points on the line.

So we have x1=0,y1=4 and x2=-8 y2=-1 this gives us =(-1-4)/(-8-0) =5/8

I don't know if this helped..

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Guys help plz i need to pass my class

m_a_m_a [10]

Answer:

x y

2 -5

3 -4

4 -3

5 -4

6 -5

Step-by-step explanation:

you had to create a x and y chart but I give u the answer

5 0

3 years ago

Take a factor out of the square root:

Allisa [31]

Answer:

Question A)

$=\sqrt{6}x$

Question B)

$=3a\sqrt{a}$

Question C)

$=5\sqrt{2}b^2$

Step-by-step explanation:

We are given:

$\sqrt{6x^2}\, \text{ where } x\geq 0$

We can rewrite the expression:

$=\sqrt{6}\cdot \sqrt{x^2}$

The square root and square will cancel each other out. Thus:

$=\sqrt{6}x$

We are given:

$\sqrt{9a^3}$

Rewrite:

$=\sqrt{9}\cdot \sqrt{a^3}$

Note that the square root of 9 is simply 3. We can also factor the second part:

$=3\cdot \sqrt{a^2\cdot a}$

Rewriting:

$=3\cdot\sqrt{a^2}\cdot\sqrt{a}$

Simplify:

$=3a\sqrt{a}$

We are given:

$\sqrt{50b^4}$

Rewrite. Note that 50 = 25(2):

$=\sqrt{25}\cdot \sqrt{2}\cdot \sqrt{b^4}$

Simplify. We can rewrite the factor as:

$=5\cdot \sqrt{2}\cdot \sqrt{(b^2)^2}$

The square and square root will cancel out. Thus:

$=5\sqrt{2}b^2$

8 0

2 years ago

What is the value of x in the equation

Alex

Answer:

D) 57

Step-by-step explanation:

1/3x- 1/2 = 18 1/2

1/3x = 19

(3) * 1/3x = 19 (3)

x = 57

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME ON THIS URGENT DO NOT WASTE ANSWERS WILL MARK BRAINLIEST

Fed [463]

Answer:

Im gonna guess 6

Step-by-step explanation:

7 0

2 years ago

Please answer this simple question!!!

vladimir1956 [14]

Just substitute the value of x from equation 2 in equation 1,
6y = x - 12
6y = 22 - 12
y= 10/6
y = 5/3

In short, Your Answer would be Option Option B) (22, 5/3)

Hope this helps!

6 0

2 years ago