Part 1We are given

. This can be rewritten as

.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula

The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is

.
The second equation is

.
We have

Factoring, we have

Equating both factors to zero.

When the value of x is 6, the value of y is

When the value of x is -3, the value of y is

Therefore, the solutions are (6,38) or (-3,11)
Answer: x = 0; y = 2; z = 5
Step-by-step explanation:
x+2y+z=9
x-y+3z=13
2z=10
==
Start with the last equation: 2z = 10, therefore z = 5 [easy]
Let's rewrite the second equation with 1) z=5, and 2) rearrange to find x:
x-y+3z = 13
x - y +3*5 = 13
x = y-2
Now use the values for x [(y-2)] and y [5] in the first equation:
X+2y+z=9
(y-2) +2y + 5 = 9
3y +3 = 9
3y = 6
y = 2
Now that we have y [2] and z [5], let's use the first equation to solve for x:
x+2y+z=9
x + 4 + 5 = 9
x + 9 = 9
x = 0
====
Try the three values (x=0, y=2, and z=5) in any of the formulas. The result should/will equal the number shown.
I would assume it would be dividing both sides by three although if someone were to actually solve this I would say multiply 2 and 3 together first.
Hope this helps :)
(8) = x +1
same thing as 8 = 1x
divide both sides by 1 and x = 8 Y= 8