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Lostsunrise [7]
3 years ago
10

Least common multiples are most helpful for

Mathematics
1 answer:
Tresset [83]3 years ago
3 0

Least common multiples are most helpful for finding common denominators in fractions

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wolverine [178]
1
{7}^{2}  +  {24}^{2}  =  {25}^{2}
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Calculate the average between 200 and 4100
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<span>4300 / 2 = 2150

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1.) what is the length of the diagonal for the given rectangular prism to the nearest whole unit?
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The answer is D.10 at least
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On the first day after the new moon, 2% of the Moon's surface is illuminated. On the second day, 6% is illuminated. Based on thi
maxonik [38]

Answer:

50%: day 13

100%: day 26

Step-by-step explanation:

We are given two days and the amount of the moon that is illuminated. The two days are points on a straight line.

(1, 0.02), (2, 0.06)

y = mx + b

m = (0.06 - 0.02)/(2 - 1) = 0.04

y = 0.04x + b

0.02 = 0.04(1) + b

b = -0.02

y = 0.04x - 0.02

We want y = 50% = 0.5

0.04x - 0.02 = 0.5

0.04x = 0.52

x = 13

y = 100% = 1

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7 0
2 years ago
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Simplify: 18q2−45q+25/9q2−25.
Svet_ta [14]

Answer:

\frac{(6q-5)}{(3q+5)}

Step-by-step explanation:

Given: \frac{18q^{2}-45q+25 }{9q^{2}-25 }

Factorizing the numerator and the denominator, we have:

18q^{2} - 45q + 25 = 18q^{2} - 30q - 15q + 25

                         = (3q - 5)(6q - 5)

and

9q^{2} - 25 = (3q - 5)(3q + 5)

So that,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}

                 = \frac{(6q-5)}{(3q+5)}

Therefore,

\frac{18q^{2}-45q+25 }{9q^{2}-25 } = \frac{(6q-5)}{(3q+5)}

5 0
3 years ago
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