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3 years ago

What is the solution to w-11=1.3

2 answers:

7 0

<span>Simplifying w + -11 = 1.3

Reorder the terms: -11 + w = 1.3

Solving -11 + w = 1.3

Solving for variable 'w'. Move all terms containing w to the left, all other terms to the right. Add '11' to each side of the equation. -11 + 11 + w = 1.3 + 11

Combine like terms: -11 + 11 = 0 0 + w = 1.3 + 11 w = 1.3 + 11

Combine like terms: 1.3 + 11 = 12.3 w = 12.3

Simplifying w = 12.3 <--- (Answer)

Happy studying ^-^</span>

pishuonlain [190]3 years ago

4 0

U can use cymath

It gives you the answer

And shows you how to do it step by step

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(-4,6); slope = -3/4

yawa3891 [41]

Answer:

y-6=-3/4(x+4)

Step-by-step explanation:

y-y1=m(x-x1)

m=-3/4

y-6=-3/4(x-(-4))

y-6=-3/4(x+4)

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3 years ago

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natulia [17]

Answer:

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3 years ago

Read 2 more answers

Write numbers to make each line have the same sum

wlad13 [49]

Answer:

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Step-by-step explanation:

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3 years ago

In a certain country, the car license plate formed by 4 numbers from the digits 1-9 followed by 3 letters from the alphabet. How

andriy [413]

Answer:

78,624,000 license plates

Step-by-step explanation:

For each of the 4 numbers, we have the following possibilities:

First number: 10 digits possible

Second number: 9 digits possible (one used)

Third number: 8 digits possible (two used)

Fourth number: 7 digits possible (three used)

For each of the 3 letters, we have the following possibilities:

First letter: 26 digits possible

Second letter: 25 digits possible (one used)

Third letter: 24 digits possible (two used)

The total number of license plates is the product of all these possibilities:

Number of plates = 10 * 9 * 8 * 7 * 26 * 25 * 24 = 78,624,000 license plates

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3 years ago

If D is midpoint of side BC of triangle ABC. P and Q are points lying respectively on side AB and AC such that DP is parallel to

LUCKY_DIMON [66]

See proof below

Step-by-step explanation:

Assume triangle ABC to have vertices at;

A(2,-1), B(2,-7) and C(6,-7)

D is midpoint of BC, thus D is at (4,-7)

The P and Q, are lying on side AB and AC, hence assume P is at (2,-4) and Q is at (4,-4) such at DP is parallel to QA

Plot the points on a graph tool and join the points to view the sketch.

To prove area of triangle CPQ is 1/4 area of ABC will be;

Find area ABC and CPQ then compare the areas.

Apply the distance formula to find the length of sides of the triangles then find the areas.

The distance formula is;

$d=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}$

Length of side AB from the sketch is;

$AB=\sqrt{(2-2)^2+(-7--1)^2} =\sqrt{-6^2} =\sqrt{36} =6units$

Length of side BC will be;

$BC=\sqrt{(-7--7)^2+(6-2)^2} =\sqrt{4^2} =\sqrt{16} =4units$

Thus area of triangle ABC will be;

1/2 *base length*height ------because it is a right-triangle

1/2*4*6=12 square units

Find the lengths of all sides of triangle CPQ

Length of side PQ is half that of side BC thus PQ=2 units

Length of side PC is;

$PC=\sqrt{(6-2)^2+(-7--4)^2} =\sqrt{4^2+-3^2} =\sqrt{16+9} =\sqrt{25} =5units$

Length of side QC will be;

$QC=\sqrt{(6-4)^2+(-7--4)^2} =\sqrt{2^2+-3^3} =\sqrt{4+9} =\sqrt{13}$

QC= √13 = 3.6 units

Find area of triangle CPQ given all sides by applying the Heron's formula for area of triangle which is;

A=√s(s-a)(s-b)(s-c) where;

A=area of the triangle

s= half the perimeter of the triangle

a=side PQ = 2 units

b=side PC = 5 units

c= side QC = 3.6 units

Finding the perimeter of triangle CPQ will be;

P=sum of all sides

P=2+5+3.6 =10.6 units

s=10.6/2 = 5.3

Area of the triangle CPQ will be;

$A=\sqrt{5.3(5.3-2)(5.3-5)(5.3-3.6)} \\A=\sqrt{5.3(3.3)(0.3)(1.7)} \\A=\sqrt{8.9} =2.98$

A=3.0 (1 decimal place)

Compare the areas;

Area of triangle ABC=12 square units

Area of triangle CPQ = 3 square units

Area of triangle CPQ / Area of triangle ABC = 3/12 =1/4

Thus you have proved that area of triangle CPQ is 1/4 th area of triangle ABC because 1/4 *12 =3

Learn More

Area of a triangle ;brainly.com/question/14869984

The Heron's formula : brainly.com/question/10713495

Keywords: midpoint, triangle, sides, parallel, prove , area, equal

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3 years ago