Resolviendo un sistema de ecuaciones, veremos que se vendieron 250 boletos de adulto.
<h3>¿Cuántos boletos de adulto fueron vendidos?</h3>
Definamos las variables:
- x = boletos de adulto vendidos.
- y = boletos de estudiantes vendidos.
Se vendieron un total de 430 boletos, entonces:
x + y = 430
Y se vendieron 70 boletos de estudiante menos que boletos de adulto:
y = x - 70
Tenemos el sistema de ecuaciones:
x + y = 430
y = x - 70
Para resolverlo, podemos reemplazar la segunda ecuación en la primera:
x + y = 430
x + (x - 70) = 430
2x = 430 + 70 = 500
x = 500/2 = 250
Se vendieron 250 boletos de adulto.
Sí quieres aprender más sobre sistemas de ecuaciones:
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Area = Side^2
Area =( 4x + 2 )^2
Area = (4x)^2 + 2(4x)(2) + (2)^2
Area = 16x^2 + 16x + 4
Thus the correct answer is option B .
Answer:
commutative property of multiplication
Step-by-step explanation:
examples of this property:
xy=yx
1*3=3*1=3
6*9=9*6=54
Answer:
4, 6, 63, 10
Step-by-step explanation:
gets mutiplied by 7
Answer:
The confidence interval at at 99% level of confidence is <em>93.7 ≤ μ ≤ 96.9</em>.<em> </em>
Step-by-step explanation:
Step 1:
We must first determine the z-value at a confidence level of 99%.
Therefore,
99% = 100%(1 - 0.01)
Thus,
α = 0.01
Therefore, the z-value will be
z_(α/2) = z_(0.01/2) = z_0.005 = 2.58
(The z-value is read-off from the z table from the standard normal probabilities.)
Step 2:
We can now write the confidence interval:
X - z_(α/2) [s/√(n)] ≤ μ ≤ X + z_(α/2) [s/√(n)]
95.3 - 2.58(6.5/√(104)) ≤ μ ≤ 95.3 + 2.58(6.5/√(104))
<em>93.7 ≤ μ ≤ 96.9</em>
Therefore, confidence interval is <em>93.7 ≤ μ ≤ 96.9 </em>which means that we are 99% confident that the true mean population lies is at least 93.7 and at most 96.9.