Answer:
14 3/4 years
Step-by-step explanation:
Let's assume compound inflation. The appropriate formula for that is:
A = P(1 + r)^t.
If we represent current prices by P, then double that would be 2P:
2P = P(1 + 0.048)^t Find t, the time required for prices to double.
Then:
2 = 1.048^t
Taking the natural log of both sides, we get:
ln 2 = t·ln 1.048, so that:
t = (ln 2) / (ln 1.048) = 14.78
At 4.8 inflation, with annual compounding, prices will double in approx. 14 3/4 years.
Answer:
<em>The mass of the steel ball is 4,235.9 gr</em>
Step-by-step explanation:
<u>Density</u>
The density ρ of a substance is a measure of its mass per unit volume:
If the density and the volume are given, the mass can be calculated by solving the above formula for m:
We know the density of pure steel ρ=8.09 gr/cm3 and the diameter of a solid steel ball d=10 cm.
We need to calculate the volume of the sphere:
The volume of a sphere of radius r is given by:
The radius is half the diameter: r= 10/2 = 5 cm. Thus:
Calculating:
The mass is:
m=4,235.9 gr
The mass of the steel ball is 4,235.9 gr
Answer:
HERE YA GO MA BOO, lol just messin dont hate
The answer is B
Step-by-step explanation:
2 times 4 = 8
Kono Dio Da!!!
Answer:
11x + 8 +8x +12 =27 (drop the parenthesis, there's no actual need for them)
19x +20 =27 (i combined like terms and then subtracted 20 from both sides)
19x = 7 (divide both sides by 19 to get x alone)
x= 7/19 or 0.36842105 (the answer)
Step-by-step explanation:
<h3>
Answer:</h3>
unshaded area = 25(4 -π) in^2 ≈ 21.46 in^2
<h3>
Step-by-step explanation:</h3>
Each of the shaded circles has a diameter of (20 in)/4 = 5 in, which also is the width of the enclosing rectangle. Then each circle has a radius of 2.5 in, and an area of ...
A = πr^2 = π(2.5 in)^2 = 6.25π in^2
The four circles together have an area of ...
4A = 4·(6.25π in^2) = 25π in^2
The area of the rectangle is the product of its length and width:
A = LW = (20 in)(5 in) = 100 in^2
Since the circles are shaded, the unshaded area is the difference between the rectangle area and the total area of the four circles:
unshaded area = (100 in^2) - (25π in^2) = 25(4 -π) in^2 ≈ 21.46 in^2
