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enyata [817]
3 years ago
14

Graph the solution to the following inequality.

Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0

Explanation= You basically do x=6 on the graph then you shade in the right side because that represents that x is GREATER THAN OR EQUAL to 6.

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In rhombus ABCD, DB=16 and AC=12. What is the perimeter of rhombus ABCD?
riadik2000 [5.3K]
DB+ DC= 32
AC+ AC =24
32+24
56
4 0
3 years ago
Please help me!!! :(
I am Lyosha [343]

Answer:

280

Step-by-step explanation:

7*5*4*2=280

4 0
3 years ago
Which function is a shrink of the exponential growth function shown on the graph?
fgiga [73]
The exponential function shown in the graph is 3^x, so (1/2)3^x is a shrink of it.

Selection B is appropriate.
3 0
3 years ago
Read 2 more answers
1 -3,45<br> Rational or irrational
Naddik [55]

Answer: rational

Step-by-step explanation:

A rational number is a number that can be expressed as a fraction. Hence 1-3.45 = - 2.45 which is - 49/20 as a fraction

6 0
3 years ago
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"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year
KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that p = 0.56

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is P(X \geq 1) when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0
3 years ago
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