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Papessa [141]
3 years ago
6

Derek is working out in order to be in shape for the upcoming football season. He does cardio exercises and strength training. E

ach hour he spends doing cardio burns 200 calories and each hour he spends doing strength training burns 100 calories. Derek's coach recommends that he spend more than twice as much time doing cardio exercises as he does doing strength training.
Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

what is the question you only gave the problem

Step-by-step explanation:

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Solve the following system: (5 points)
posledela
I wish I could help but I didn’t learn that
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3 years ago
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Solve the equation y. 6=2(y+2)
atroni [7]

Answer:

y = 1

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    6-(2*(y+2))=0

Step by step solution :

Equation at the end of step  1  :

 6 -  2 • (y + 2)  = 0

Pulling out like terms :

3.1     Pull out like factors :

  2 - 2y  =   -2 • (y - 1)

Equation at the end of step  3  :

 -2 • (y - 1)  = 0

Equations which are never true :

4.1      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.2      Solve  :    y-1 = 0

Add  1  to both sides of the equation :

                     y = 1

One solution was found :

                  y = 1

Processing ends successfully

plz mark me as brainliest :)

6 0
3 years ago
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What is a better buy- a popsicle at $0.75 or a popsicle at 70¢ and why? Group of answer choices The popsicle that is 70¢ because
xeze [42]

Answer:

70 cents

Step-by-step explanation:

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3 years ago
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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
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HELP PLEASE!
navik [9.2K]
1. 
20= 2(x-4)
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