I wish I could help but I didn’t learn that
Answer:
y = 1
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
6-(2*(y+2))=0
Step by step solution :
Equation at the end of step 1 :
6 - 2 • (y + 2) = 0
Pulling out like terms :
3.1 Pull out like factors :
2 - 2y = -2 • (y - 1)
Equation at the end of step 3 :
-2 • (y - 1) = 0
Equations which are never true :
4.1 Solve : -2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : y-1 = 0
Add 1 to both sides of the equation :
y = 1
One solution was found :
y = 1
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Answer: 
Step-by-step explanation:
We know that the standard quadratic equation is ax^2+bx+c=0
Let's compare all the given equation to it and , find discriminant.
1. a=2, b= -7, c=-9
So it has 2 real number solutions.
2. a=1, b=-4, c=4

So it has only 1 real number solution.
3. a=4, b=-3, c=-1

So it has 2 real number solutions.
4. a=1, b=-2, c=-8
So it has 2 real number solutions.
5. a=3, b=5, c=3

Thus it does not has real solutions.
1.
20= 2(x-4)
20/2= 2(x-4)/2
10= x-4
+4 . +4
14=x