Answer:
The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius.
Step-by-step explanation:
hope this helps you :)
I think it’s 15 sorry if I’m wrong
Answer:
6
Step-by-step explanation:
We have to use Pythagoras' identity twice to find y
The square on the hypotenuse is equal to the sum of the squares on the other two sides.
In right triangle MUT to find TU
TU² + 3² = 6², that is
TU² + 9 = 36 ( subtract 9 from both sides )
TU = 27 ( take the square root of both sides )
TU =
=
= 3
In right triangle NUT to find y
y² = 9² + (3
)² = 81 + 27 = 108 ( take the square root of both sides )
y =
=
= 6
Answer:
thanks:)
Step-by-step explanation:
hehe