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3 years ago

The sum of two integers is -4. Can the two integers both be negative? Explain

Mathematics

1 answer:

timurjin [86]3 years ago

7 0

Answer:

no they cannot

Step-by-step explanation:

You aren't able to have 2 integers that are negative. You would need 1 positive and one negative integer, so when you add them together, you get a negative outcome, providing that the negative number is more than the positive number.

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Complete the equation of the line through (-6,5) and (-3, -3). Use exact numbers.

Arada [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

Fatima deposits $600 in an account that pays 3.65% annual interest compounded daily. Use the fact that there are approximately 3

seropon [69]

A=600⋅(1.0001)^365t
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3 0

3 years ago

Tammy borrowed $5000 at a rate of 12% compounded monthly. Assuming she makes no payments, how much will she owe after 9 years?

Dominik [7]

Answer:

$14,644.63

Step-by-step explanation:

To solve this problem we can use the compound interest formula which is shown below:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate

n = number of times compounded annually

t = time

First change 12% into a decimal:

12% -> $\frac{12}{100}$ -> 0.12

Lets plug in the values:

$A=5,000(1+\frac{0.12}{12})^{9(12)}$

$A=14,644.63$

Tammy will own $14,644.63 after 8 years,

5 0

3 years ago

The diameters of cherry tomatoes produced by a large farm have an approximately Normal distribution, with a

Citrus2011 [14]

Answer: D. 0.9967

Step-by-step explanation: To solve this, you need to do the z-score formula with both numbers. So 30-22/2.5 = 3.2. On the z-score chart, that equals .9993. Hold onto that number. Then you do the same with 15. 15-22/2.5 = -2.8. On the z score chart, that equals .0026. Subtract those numbers. .9993 - .0026 = .9967. It's not as compacted as it looks <3

7 0

3 years ago

A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w

DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 21.5, \sigma = 4.7$

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.175*4.7$

$X = 27.0225$

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.04*4.7$

$X = 26.388$

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0

3 years ago