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2 years ago

Math question help pls

Mathematics

1 answer:

valentina_108 [34]2 years ago

3 0

Answer:

The fourth answer: A person's weight, w, on the moon is 1/6 her weight on Earth, e.

Step-by-step explanation:

The equation must be translated carefully into word form.

Her weight on Earth is represented by e.

"e x 1/6" into "1/6 her weight on Earth, e"

Her weight on the moon is represented by w.

"= w" into "A person's weight, w, on the moon is"

Another way to translate: 1/6 of a person's weight on Earth, e, is equal to her weight on the moon, w.

I hope this helped :)

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Unit rate for 3 ounces for every 3/4 cup

Vanyuwa [196]

Answer:

4 ounces per cup

Step-by-step explanation:

To find the unit rate, we take the ounces and divide by cups. We want a 1 in the denominator

3 ounces÷3/4 cup

Copy dot flip

3 ounces * 4/3 per cup

4 ounces per cup

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3 years ago

Line a is represented by the equation y=−2x+3 .

Daniel [21]

Y = -2x + 5 is parallel to line as the slopes ( = -2) are the same.

the other 2 lines are nether parallel or perpendicular

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2 years ago

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The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

posledela

Step-by-step walkthrough:

Well a standard half-life equation looks like this.

$N = N_0 * (\frac{1}{2})^{t/p$

$N_0$ is the starting amount of parent element.

$N$ is the end amount of parent element

$t$ is the time elapsed

$p$ is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days$

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g$

Now we just gotta do some algebra. Use the original function but this time, replace $N(t)$ with 10g and solve algebraically.

$10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}$

Take the log of both sides.

$log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})$

Use the exponent rule for log laws that, $log(b^x) = x*log(b)$

$log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})$

$\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}$

$2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t$

slap that in your calculator and you get

$t = 8.1 days$

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1 year ago

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bazaltina [42]

Answer:

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2 years ago

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21, it says it right in the name.

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