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4 years ago

Explain how ethene is a feedstock for making ethanol.

1 answer:

Ber [7]4 years ago

8 0

Ethene can react with steam to create ethanol under certain conditions. In this reaction, ethene can be considered a feedstock as it is a reactant so you need to use it to get the ethanol you want.

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A 6.7 kg object moves with a velocity of 8 m/s. What's its kinetic energy? A. 26.8 J B. 214.4 J C. 167.5 J D. 53.6 J

expeople1 [14]

KE= .5*M*V^2
.5*6.7*8^2
=214.4 Joules

7 0

4 years ago

Read 2 more answers

Calculate the correct fuse that should be used for a 230V,1KW electric hair dryer.

zzz [600]

Answer: 4 A

Explanation:

Given

Voltage $V=230\ V$

Power $P=1\ kW$

Power is given by $P=VI\\$

Insert the values

$\Rightarrow 1000=230\times I\\\\\Rightarrow I=\dfrac{1000}{230}\\\\\Rightarrow I=3.84\ A$

The rating of fuse is slightly higher than the normal operating conditions. Therefore, a 4 A fuse should be used here.

6 0

3 years ago

the declaration of Independence discusses the protection of natural rights. These rights include the right life liberty and the

nikdorinn [45]

Answer:

i can't understand ur question

4 0

3 years ago

A 4.2-g bullet is fired at a speed of 370 m/s into a stationary lead block, which moves a distance of 1.2 m before coming to res

Natali5045456 [20]

Answer:

(a) F = 239.575 N (b) t = 0.00649s or 6.49 ms

Explanation:

(a) By law of energy conservation, the bullet kinetic energy will be transferred to work done on stopping it from moving.

Formula for Kinetic Energy $E_k = \frac{mv^2}{2}$ where m is bullet mass, v is the velocity

Formula for work $W = FS$ where F is the average force and S is the distance travelled.

$E_k = W$

$\frac{mv^2}{2} = FS$

$F = \frac{mv^2}{2S}$

Substitute m = 4.2 g = 0.0042 kg, v = 370 m/s and S = 1.2 (m)

$F = \frac{0.0042*370^2}{2*1.2} = 239.575 N$

(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

$a = \frac{F}{m} = \frac{239.575}{0.0042} = 57041.67 (m/s^2)$

We also have $v(t) = v_0 + at$

At the time the bullet is coming to rest, $v(t) = 0, a = -57041.67 m/s^2$

Therefore, $0 = 370 - 57041.67t$

$t = \frac{370}{57041.67} = 0.00649 s = 6.49 ms$

3 0

4 years ago

A railroad car of mass 2.00 3 104 kg moving at 3.00 m/s collides and couples with two coupled railroad cars, each of the same ma

FrozenT [24]

Given:

Mass of the rail road car, m = 2 kg

velocity of the three cars coupled system, v' = 1.20 m/s

velocity of first car, $v_{a}$ = 3 m/s

Solution:

a) Momentum of a body of mass 'm' and velocity 'v' is given by:

p = mv

Now for the coupled system according to law of conservation of momentum, total momentum of a system before and after collision remain conserved:

$mv_{a} + 2mv_{b} = (m + 2m)v'$ (1)

where,

$v_{a}$ = velocity of the first car

$v_{b}$ = velocity of the 2 coupled cars after collision

Now, from eqn (1)

$v' = \frac{v_{a} + 2v_{b}}{3}$

$v' = \frac{3.00 + 2\times 1.20}}{3}$

v' = 1.80 m/s

Therefore, the velocity of the combined car system after collision is 1.80 m/s

7 0

3 years ago

Read 2 more answers