Answer:
correct option is C. 1700 - 2300
Explanation:
solution
according to Care stream, exposure indicators provide the technical adequancy incident radiations on the x ray
and we muse care stream formula that is
Exposure Index EI = 1000 × 
+ 2000
here 1 mR = 2000 EI
and 2 mR = 2300 EI
and 3 mR = 1700 EI
so here acceptable range of exposure indicators is 1700 - 2300
correct option is C. 1700 - 2300
Heat is transferred by a fluid's macroscopic movement, which is known as convection. Weather systems and forced-air furnaces both use this form of transmission. Thus, option A is correct.
<h3>What Convection method of heat transfer warms?</h3>
Convection, as heat is transmitted through the sand's solid structure. Conduction, as the air particles that come into contact with the hot sand travel more quickly.
The heat is transferred inside the fluid during convection. Heat transfer in radiation happens by electromagnetic waves without the use of particles.
Conduction, as heat is transferred using electromagnetic waves Convection, since heat is transferred by air particles without the usage of a medium.
Therefore, Convection, because heat is transferred through the solid sand.
Learn more about Convection here:
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Answer:
ρ=3000 kg/m
Explanation:
My work is in the attachment.
Density is just the mass of an object/substance divided by its volume. Technically you could just divide the kg by L and be done with it, but the standard units for volume are m³. So I converted it before calculating.
Answer:
Is a mixture of all visible light.
Explanation:
The sunlight is a mixture of all colors. Rainbows are light from the sun and are made up of red, orange, yellow, green, blue, violet. The sun produce also ultraviolet waves because of its high temperature.
Answer:
a.241.08 m/s b. 196 Hz c. 392 Hz
Explanation:
a. Determine the speed of waves within the wire.
The frequency of oscillation of the wave in the string, f = nv/2L where n = harmonic number, v = speed of wave in string, L = length of string = 1.23 m.
Since f = 588 Hz which is the 6 th harmonic, n = 6. So, making v subject of the formula, we have
v = 2Lf/n
substituting the values of the variables into v. we have
v = 2 × 1.23 m × 588Hz/6
v = 241.08 m/s
b. Determine the frequency at which the wire will vibrate with the first harmonic wave pattern.
The first harmonic is obtained from f when n = 1,
So, f = v/2L = 241.08 m/s ÷ 1.23m = 196 Hz
c. Determine the frequency at which the wire will vibrate with the second harmonic wave pattern.
The second harmonic f' = 2f = 2 × 196 Hz = 392 Hz
