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3 years ago

Which factors affect the gravitational force between objects? Check all that apply.

Physics

2 answers:

storchak [24]3 years ago

6 0

Answer:

the answer is C and D

Explanation:

did it on edge

hope u have better day than me

hope this helps

drek231 [11]3 years ago

4 0

Explanation:

distance between both objects and masses of the objects

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10000 dyne into Newton.

Igoryamba

Divide the value by 100000 because;
1 Newton = 100000 Dyne

$\sf\therefore \: 10000 \: dyne = \frac{10000}{100000} = 0.1 \: newton$

8 0

2 years ago

A train is traveling down a straight track at 20. m/s when the engineer applies the brakes, resulting in an acceleration of -1.0

Kipish [7]

Answer:

The answer to your question is: d = 0 m, it does not move

Explanation:

Data

vo = 20 m/s

a = -1 m/s2

t = 40 s

d = ?

Formula

d = vot + (1/2)at²

Substitution

d = (20)(40) + (1/2)(-1)(40)²

d = 800 - 800

d = 0 m It suggest that it does not move.

I hope it can help you

7 0

3 years ago

What is the name of the ratio of the voltage applied to a circuit and the current in a circuit

malfutka [58]

Resistance is the name of the ratio of the voltage applied to a circuit and the current in a circuit. Goes under Ohm's Law

4 0

4 years ago

The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?

xxMikexx [17]

Answer:

Q = 675 [J]

Explanation:

We can calculate the amount of heat transfer by means of the following expression that includes the mass and temperature change in a body as a function of the specific heat.

$Q=m*C_{p}*(T_{initial}-T_{final})$

where:

m = mass = 25 [gr]

Cp = specific heat = 0.9 [J/g*°C]

Tinitial = 55 [°C]

Tfinal = 25 [°C]

$Q=25*0.9*(55-25)\\Q=675 [J]$

4 0

3 years ago

A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position

irga5000 [103]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

Mass of the ball, m = 2.4 kg

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

$f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz$

The angular frequency of the oscillation is calculated as follows;

$\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s$

The force constant of the spring is calculated as follows;

$\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m$

Learn more about general wave equation here: brainly.com/question/25699025

4 0

3 years ago